Answer:
The solution for the given problem is done below.
Explanation:
M1 = 2.0
= 0.3636
= 0.5289
= 0.7934
Isentropic Flow Chart: M1 = 2.0 ,
= 1.8
T1 =
(1.8)(288K) = 653.4 K.
In order to choke the flow at the exit (M2=1), the above T0* must be stagnation temperature at the exit.
At the inlet,
T02=
= (1.8)(288K) = 518.4 K.
Q= Cp(T02-T01) =
= 135.7*
J/Kg.
Answer:
ICP -OES stand for inductively coupled plasma optical emission spectroscopy
Explanation:
It is techniques that known as trace level technique which help to identify and quantify the element present in sample by using spectra emission.
The analysis process include desolvates, ionization and excitation of the sample. The sample is identify by analyzing the emission line from it and quantify by analyzing the intensity of same emission lines.
Answer:
Output signal shape: square, from 0.1 to 230 MHz. Output power: -10 dBm (at a load of 50 Ohms).
Explanation: