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erastovalidia [21]
3 years ago
6

Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

The answer is

<h2>1.38 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

density =  \frac{138}{100}  = \frac{69}{5 0}

We have the final answer as

<h3>1.38 g/mL</h3>

Hope this helps you

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820 g Li2SO4 is dissolved into 2500 mL of solution. What is the molar concentration?
Andreas93 [3]

Molarity is defined as the moles of solute per liter of solution. M=\frac{n}{V}. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of Li_2SO_4 which is 109.98 g/mol

Li_2SO_4= 2 \times Li_{Ar} + S_{Ar} + 4 \times O_{Ar}\\= (2 \times 6.941 + 32.1 + 4 \times 16.0) = 109.98 g/mol

820\ g\ Li_2SO_4 \times \frac{mol}{109.98\ g}= 7.46\ mol\ Li_2SO4

Then we find the molarity using above equation

M= \frac{n}{V} = \frac{7.46 mol}{2500ml} \times\frac{1000ml}{L} = 2.98\ M


6 0
4 years ago
Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr
Alecsey [184]

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}, where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

5 0
3 years ago
The Formation Of Lithium Iodide
IRISSAK [1]

<u>Lithium Iodide</u><u>:</u>

~formed by the reaction of hydroxide with hydroiodic acid

Hope this helped you, have a good day bro cya)

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3 years ago
What is the difference between atomic mass, relative atomic mass and average atomic mass
vesna_86 [32]

\bold{\huge{\underline{\purple{ Answer }}}}

<u>Difference </u><u>between </u><u>Atomic </u><u>mass</u><u>, </u><u>relative </u><u>atomic </u><u>mass </u><u>and </u><u>average </u><u>atomic </u><u>mass</u><u> </u><u>:</u><u>-</u>

<h3><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Atomic mass is the mass of neutrons and protons present in the nucleus of an atom .
  • It is always calculated for a single element and having direct value
  • For isotopes also, the atomic mass is calculated separately . Example :- <u>Carbon </u><u>1</u><u>2</u><u> </u><u>,</u><u> </u><u>carbon </u><u>1</u><u>3</u><u> </u><u>and </u><u>carbon </u><u>1</u><u>4</u><u> </u><u>have </u><u>different </u><u>atomic </u><u>mass</u><u>. </u>
  • The SI unit of Atomic mass is " u" and "amu"

<h3><u>Relative </u><u>Atomic </u><u>mass </u><u>:</u><u>-</u></h3>

  • Relative atomic mass is mean mass of the atoms of an element which is compared to the 1/12th mass of carbon - 12 .
  • Carbon - 12 is taken as a relative when we calculate the relative atomic mass of any element
  • For calculating relative atomic mass, we need to know the masses, percentage and abundance of all types of elements
  • Relative atomic mass is a dimension less quantity

<h3><u>Average </u><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Average atomic mass is the average mass of an atoms of a particular element by considering it's isotopes
  • While we calculate average atomic mass is a standardized number. Whereas, Average atomic mass sometimes varies geologically .
  • It also includes percentage, abundance and masses of given element .
  • In average atomic mass, We do not compare mean value with the 1/12 mass of carbon - 12
  • The unit of Average atomic mass is "Amu" or " u " .
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