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erastovalidia [21]
3 years ago
6

Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.

Chemistry
1 answer:
nlexa [21]3 years ago
7 0

Answer:

The answer is

<h2>1.38 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

density =  \frac{138}{100}  = \frac{69}{5 0}

We have the final answer as

<h3>1.38 g/mL</h3>

Hope this helps you

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Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro
vitfil [10]

Answer : The partial pressure of O_2 is, 222.93 torr

Explanation :  

Half-life = 2.81 hr = 168.6 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{168.6min}

k=4.11\times 10^{-3}min^{-1}

Now we have to calculate the partial pressure of O_2

The balanced chemical reaction is:

                           2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Initial pressure   760                0             0

At eqm.             (760-2x)            4x            x

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{P_o}{P_t}

where,

k = rate constant

t = time passed by the sample  = 215 min

a = initial pressure of N_2O_5 = 760 torr

a - x = pressure of N_2O_5 at equilibrium = (760-2x) torr

Now put all the given values in above equation, we get:

215=\frac{2.303}{4.11\times 10^{-3}}\log\frac{760}{760-2x}

x=222.93torr

The partial pressure of O_2 = x = 222.93 torr

7 0
3 years ago
Answers for cardiovascular system crossword puzzle
KengaRu [80]
I dont know the answer

5 0
3 years ago
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Help me with this question please !!<br> A<br> B <br> C<br> D
RUDIKE [14]

Answer:

c becuase I'm not to good at this but I'm pretty sure

Explanation:

I think

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2 years ago
What quality is attributed to water due to “capillary action”?
irakobra [83]

Answer:

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4 0
2 years ago
Use the unbalanced equation NH3+O2=NO+H2O to find the mole ratio between NO and H2O
Leona [35]

Answer:

For every 4 moles of NO created, 6 moles of H2O are created so the ratio is 4:6

Explanation:

You just need to balance the equation.

NH3 + O2 -> NO + H2O

1. I started with hydrogen; there's 3 on the left and 2 on the right. Multiply them together to find a number they both go into (3×2=6, but in this case 6 hydrogen on each side does not work so I doubled it so there is 12 hydrogen on each side).

This will bring you to this:

4NH3 + O2 -> NO + 6H2O

2. Now get equal amounts of nitrogen on each side. There's 4 nitrogen on the left side, and 1 on the right. Multiply the right by 4. Then you will have this:

4NH3 + O2 -> 4NO + 6H2O

3. Last thing you need to do is have the same amount of oxygen on both sides. On the left you have 2 and on the right you have 10. Get the left to 10 by multiplying it by 5.

Balanced: 4NH3 + 5O2 -> 4NO + 6H2O

In word form, for every reaction between 4 moles of ammonia and 5 moles of oxygen, 4 moles of nitric oxide and 6 moles of water will be created.

I hope this helps!

5 0
3 years ago
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