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kirza4 [7]
3 years ago
11

In your own words, define a fire. What is a fire?

Chemistry
2 answers:
Bess [88]3 years ago
8 0

Answer:

This would depend on the intensity or the size of a fire.

Explanation:

For instance, a small fire could be described as: kindled, flickering, dancing (in the case of a candle flame), smoldering, or crackling.

A medium size fire, such as a camp fire or a fireplace could be described as: crackling, blazing, burning, or roaring.

While a large or very intense fire (such as a forest fire or a house fire) could be described as: roaring, blazing, burning out of control, consuming, raging, or destroying.

If you were more looking for synonyms of ‘fire’, here are a few of my favorites: flame, blaze, incinerate, immolation, and inferno. (Edited to add a few I remembered: pyre, conflagration, and scorching.)

bulgar [2K]3 years ago
5 0

Answer:

Fire is something that's red and sorta orange is hot and can burn you but fire can be good and bad at some points for example fire can be used as a campfire,fireplace at home,and lighting candles. Fire is also very dangerous tho ,you can burn yourself if your not careful it can light your house on fire and that wouldn't be very safe. In simple words i would say fire is something that can have advantages and disadvantages.

Ahhh hope thats alright im on online classes but i wanted to help!!

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During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
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Y_Kistochka [10]

Answer:

Explanation:

Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts with oxygen. What is the limiting reactant in this experiment?

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first, balance the equation

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two magnesium atoms react with one diatomic oxygen molecule

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but we have 2 moles of magnesium atoms and 2X5 = 10 moles of oxygen atoms

the lesser magnesium LIMITS the amount of product we can make, so it is the LIMITING REAGENT.

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