The resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms)
Explanation:
In the United States Of America the standard voltage is 120 v and their frequency is 60 Hz
Standard wall outlet voltage is 120 V
The current in the lamp is 0.5 ampere
Resistance (R) = V/ I
= 120/0.5
= 240Ω (ohms)
Thus the resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms).
Answer:
W = F * s
Work done equals applied force * distance traveled
Apparent weight = M g (1 - sin θ) since some of applied force will lighten sled
μ = coefficient of kinetic friction
F cos θ = force applied to motion of sled
s = distance traveled
[μ M g (1 - sin θ)] cos θ * s = work done in moving sled
Note that F = μ M g if applied force is in the horizontal direction
Velocity because it gives the displacement and time
Answer:
88.34 N directed towards the center of the circle
Explanation:
Applying,
F = mv²/r................... Equation 1
F = Force needed to keep the mass in a circle, m = mass of the mass, v = velocity of the mass, r = radius of the circle.
But,
v = 2πr/t................... Equation 2
Where t = time, π = pie
Substitute equation 2 into equation 1
F = m(2πr/t)²/r
F = 4π²r²m/t²r
F = 4π²rm/t²............. Equation 3
From the question,
Given: m = 0.8 kg, r = 0.7 m, t = 0.5 s
Constant: π = 3.14
Substitute these values into equation 3
F = 4(3.14²)(0.7)(0.8)/0.5²
F = 88.34 N directed towards the center of the circle
Answer:
Explanation:
a.
b. R3= 1/2R2=6 ôm
R12= R1+R2=20 ôm
Rtđ=R12.R3/R12+R3= 4,62 ôm
c. U= I.Rtđ = 2.4,62=9,23 V
I1=I2= 9,23/20= 0,4615 A
I3= 2-0,4615=1,5385 A
