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2 years ago

10. Which of these requires a wheel alignment after replacement?

Engineering

2 answers:

son4ous [18]2 years ago

8 0

Answer: c both

Explanation:

because the wheel needs struts/shocks when it on the mountain

Elden [556K]2 years ago

5 0

C. Both; require a wheel alignment after replacement

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A right triangle has a height of 20 centimeters and a base of 10 centimeters. What is the área of the triangle

zmey [24]

Answer:

100 cm

Explanation:

...........................

6 0

2 years ago

A 3-oz serving of roasted, skinless chicken breast contains 140 Cal, 27 g of protein, 3 g of fat, 13 mg of calcium, and 64 mg of

Art [367]

Answer:

Explanation:

a) Given C [ cal pro fat calc sod]

[140 27 3 13 64]

P = [cal pro fat calc sod]

[180 4 11 24 662]

B = [cal pro fat calc sod]

[50 5 1 82 20]

To find C+2P+3B = [140 27 3 13 64] + 2[180 4 11 24 662] + 3[50 5 1 82 20]

= [650 54 28 307 1448]

The entries represent skinless chicken breast , One-half cup of potato salad and One broccoli spear.

7 0

3 years ago

You have the assignment of designing color codes for different parts. Three colors are used on each part, but a combination of t

Masja [62]

Answer:

7 available

Explanation:

Since 3 colors are available r = 3

Total combination = 35

nCr = 35 ---1

nCr = n!/(n-r)!r!---2

We put equation 1 and 2 together

n-1)(n-2)(n-3)!/n-3)! = 35x 3!

We cancel out (n-3)!

(n-1)(n-2) = 210

7x6x5 = 210

nC3 = 35

7C3 = 35

So If there are 35 combinations, 7 colors are available.

Thank you!

3 0

2 years ago

A BOD test is run using 30 mL of wastewater and 270 mL of dilution water. The initial DO of the mixture is 9.0 mg/L. After 5 day

erma4kov [3.2K]

D Hey will you please help me with my essay and I’ll get back to yours please ASAP

3 0

3 years ago

water flows in a horizontal constant-area pipe; the pipe diameter is 75 mm and the average flow speed is 5 m/s. At the pipe inle

Veronika [31]

Answer:

Head loss = 28.03 m

Explanation:

According to Bernoulli's theorem for fluids we have

$\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=Constant$

Applying this between the 2 given points we have

$\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}=\frac{P_{2}}{\gamma _{w}}+\frac{V_{2}^{2}}{2g}+z_{2}+h_{l}$

Here $h_{l}$ is the head loss that occurs

$\therefore h_{l}=\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}-\frac{P_{2}}{\gamma _{w}}-\frac{V_{2}^{2}}{2g}-z_{2}$

Since the pipe is horizantal we have $z_{1}-z_{2}=0$

Applying contunity equation between the 2 sections we get

$A_{1}V_{1}=A_{2}V_{2}\\\\\therefore V_{1}=V_{2}(\because A_{1}=A_{2})$

Since the cross sectional area of the both the sections is same thus the speed

is also same

Using this information in the above equation of head loss we obtain

$h_{l}=\frac{1}{\gamma _{w}}(P_{1}-P_{2})$

Applying values we get

$h_{l}=\frac{1}{9810}\times (275\times 10^{3})m\\\\\therefore h_{l}=28.03m$

3 0

3 years ago