Answer:
Fatigue occurs under conditions of high elastic stress, high stress fluctuations and high rate of loading
Explanation:
According to many definition of fatigue failure the fatigue occurs when in an especifyc point of the object there is involved many forces and tensions.
That tensions needs to be big in magnitud, de variations of the efforts it has to be with a lot of amplitude and the loading in the object it has to be with a lot of number of cycles.
If in the all of these three conditions are present the fatigue failure it would appear.
Answer:
See explaination
Explanation:
Kindly check attachment for the step by step solution of the given problem.
I need help my self lol XD
Answer:
a. V = 109.64 × 10⁵ ft/min
b. Mw = 654519.54 kg/hr
Explanation:
Given Parameters
mass flow rate of water, Mw = 90000g/min = 6607.33 kg/s
inlet temperature of water, T1 = 84 F = 28.89 C
outlet temperature of water, T2 = 68 F = 20 C
specific heat capacity of water, c = 4.18kJ/kgK
rate of heat remover from water, Qw is given by
Qw = 6607.33[28.89 - 20] * 4.18
Qw = 245529.545kw
For air, inlet condition
DBT = 70 F hi = 43.43 kJ/kg
WBT = 60 F wi = 0.00874 kJ/kg
u1 = 0.8445 m/kg
oulet condition,
DBT = 70 F RH = 100.1
h1 = 83.504kJ/kg
Wo = 0.222kJ/kg
check the attached file for complete solution
Answer:
T₂ =93.77 °C
Explanation:
Initial temperature ,T₁ =27°C= 273 +27 = 300 K
We know that
Absolute pressure = Gauge pressure + Atmospheric pressure
Initial pressure ,P₁ = 300+1=301 kPa
Final pressure ,P₂= 367+1 = 368 kPa
Lets take temperature=T₂
We know that ,If the volume of the gas is constant ,then we can say that


Now by putting the values in the above equation we get

The temperature in °C
T₂ = 366.77 - 273 °C
T₂ =93.77 °C