Answer:
It will be around 146,27 min since the pump is turned on until the deck is clear of the water.
Explanation:
When the leak is discovered and the pump is turned on, the lower deck is already submerged and the leak is not fixed; then, in order to have the deck clear of water, the bilge pump has to remove the <em>accumulated water </em>(
) and the <em>water that is taking on</em> (
) through the leak. We can represent this mathematically as follow:
<em>Equation 1</em>
Where:
: is the accumulated water when the leak was discovered
: is the takes on rate through the leak = 57.5 gal/min
: is the removing rate of the bilge pump = 73.8 gal/min
t= is the time since the pump is turned on until the deck is clear of water.
To calculate the accumulated water (), we will model the lower deck as a flat-bottomed container with a bottom surface area of 510 
and straight vertical sides. Knowing that the level submerged is 7.5 inches, and performing the corresponding unit conversions, we obtain:
= bottom surface area * lever submerged
<em>Equation 2</em>
Solving equation 1 for time (t), and replacing the value obtained in equation 2, we get:
146,27 min
Answer:
For example, a 5W- motor oil will flow better at lower temperatures than a 15W- motor oil. The higher number, following the “w” refers to hot weather viscosity, or how fluid your oil is at hot temperatures. The higher the number, the thicker the oil at a specified temperature. so it's B
Explanation:
Answer:
Technician B
Explanation:
When working on vehicles which are equipped with a catalytic coverter, the best practice of asphyxiating someone is to use carbon monoxide. This implies that you need an extraction sytem. Therefore, technician A is wrong by assuming no need of the system. In conclusion, technician B is correct.
Answer:
The break force that must be applied to hold the plane stationary is 12597.4 N
Explanation:
p₁ = p₂, T₁ = T₂
The heat supplied = 
× Heating value of jet fuel
The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s
The heat supplied = 
· 
= 20 kg/s
The heat supplied = 20* = 21,350 kJ/s
= 1.15 kJ/kg
T₃ = 21,350/(1.15*20) + 485.03 = 1413.3 K
p₂ = p₁ × p₂/p₁ = 95×9 = 855 kPa
p₃ = p₂ = 855 kPa
T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K
T₄ = 1413.3 - 204.88 = 1208.42 K
T₅ = 1208.42*(2/2.333) = 1035.94 K
= √(1.333*287.3*1035.94) = 629.87 m/s
The total thrust = × 
= 20*629.87 = 12597.4 N
Therefore;
The break force that must be applied to hold the plane stationary = 12597.4 N.
