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3 years ago

What are the two safety precautions taken before driving a car

Engineering

1 answer:

nydimaria [60]3 years ago

7 0

<em>Answer:</em>

<h3><em>1. Check mirrors</em></h3><h3><em>2. Put on your seat belt</em></h3>

<em>Explanation:</em>

<em>1. Checking your mirrors are very important because if someone screwed with them then it can mess up your driving. </em>

<em />

<em>2. Putting on your seat belt is a law so you must put it on and it can save your life one day. </em>

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A displacement transducer has the following specifications: Linearity error ± 0.25% reading Drift ± 0.05%/○C reading Sensitivity

White raven [17]

Answer:

The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

Explanation:

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

assume from specifications that k = 5v/5cm

= 1v/cm

u^2 = (0.0025*2)^(2) + (0.005*10*2)^2 + (0.0025*2)^2

= 0.01225v

v = 2v * 0.001

= 0.002v

uncertainty in a nominal displacement

= (u^2 + v^2)^(1/2)

= ((0.01225)^2 + (0.002)^2)^(1/2)

= 0.0124 cm

Therefore, The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm

8 0

3 years ago

A commuter train traveling at 50 mi/h is 3 mi from a station. The train then decelerates so that its speed is 15 mi/h when it is

jonny [76]

Answer:

a) $t = 277.477\,s\,(4.625\min)$ , b) $v_{f} = 0\,\frac{mi}{h}$ , c) $a = -0.128\,\frac{ft}{s^{2}}$

Explanation:

a) The deceleration experimented by the commuter train in the first 2.5 miles is:

$a=\frac{[(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot (\frac{1\,h}{3600\,s} )]^{2}-[(50\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot (\frac{1\,h}{3600\,s} )]^{2}}{2\cdot (2.5\,mi)\cdot (\frac{5280\,ft}{1\,mi} )}$

$a = -0.185\,\frac{ft}{s^{2}}$

The time required to travel is:

$t = \frac{(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,fi} )\cdot(\frac{1\,h}{3600\,s} )-(50\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,fi} )\cdot(\frac{1\,h}{3600\,s} )}{-0.185\,\frac{ft}{s^{2}} }$

$t = 277.477\,s\,(4.625\min)$

b) The commuter train must stop when it reaches the station to receive passengers. Hence, speed of train must be $v_{f} = 0\,\frac{mi}{h}$ .

c) The final constant deceleration is:

$a = \frac{(0\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot(\frac{1\,h}{3600\,s} )-(15\,\frac{mi}{h} )\cdot (\frac{5280\,ft}{1\,mi} )\cdot(\frac{1\,h}{3600\,s} )}{(2.875\,min)\cdot (\frac{60\,s}{1\,min} )}$

$a = -0.128\,\frac{ft}{s^{2}}$

7 0

3 years ago

A Service Schedule is...

VikaD [51]

Answer:

option c

Explanation:

8 0

3 years ago

Read 2 more answers

You are in charge of ordering the concrete for a basement wall concrete pour. The wall forms are all set up and ready. The wall

choli [55]

Answer:

189.15cy

Explanation:

To understand this problem we need to understand as well the form.

It is clear that there is four wall, two short and two long.

The two long are $\rightarrow 120ft5in+2(10ft)$

The two long are $\rightarrow 122ft1in=122.08ft$

The two shors are $\rightarrow 86ft4.5in = 86.375ft$

The height and the thickness are 14ft and 0.83ft respectively.

So we only calculate the Quantity of concrete,

$Q_c = [(2*122.08)+(2*86-375)]*14*0.833\\Q_c=4864.02ft^3$

That in cubic yards is equal to $180.15 (1cy=27ft^3)$

Hence, we need order 5% plus that represent with the quantity

$Q_{ordered}=1.05*180.15=189.15cy$

8 0

3 years ago

Birdie Par owns a company that makes golf gloves. She is thinking about introducing a new glove, which would require an addition

melamori03 [73]

Birdie's company will make a profit of $30,000 if she sells 3,000 gloves at the $15 price.

Step-by-step Solution:

Break even point= fixed cost/ selling price - variable cost

here the fixed cost is= $20,000

selling price= $15 and variable cost = $5

BEP= 20,000/ 15-5= 20,000/10= 2000 units

b. if they sell 3000 gloves, the contribution profit will be

total revenue= 3000*$15= $45,000

contribution= selling price- variable cost, 15-5= $10 per unit

the profit is= 3000*$10= $30,000

What is variable cost?

A variable cost is one that varies in relation to either the volume of production or the number of services provided. There should be no variable costs if no production or services are provided. Variable costs should rise in tandem with increases in production or services.

To learn more about Profit Calculation, visit: brainly.com/question/28177180

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3 0

1 year ago

What are the two safety precautions taken before driving a car​

What are the two safety precautions taken before driving a car