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butalik [34]
3 years ago
8

In which of the following choices is the oxidation number incorrect?

Chemistry
1 answer:
8_murik_8 [283]3 years ago
4 0

Cl2(s); oxidation number 1 is the incorrect choices in oxidation number.

Explanation:

In the elemental form oxidation state is zero. Here chlorine is present in elemental form so oxidation state is zero.

Oxidation number depends on the number of electrons gained or lost by an atom of the element say in compound formation.

If electron is gained oxidation number becomes negative.

If electron is lost then oxidation number is positive.

If the octet rule is fulfilled that valence shell is filled them atomic number gets zero. Since Cl2 is in neutral state the oxidation number is 0.

Oxidation number in general can be made out by checking the valency of the element as oxidation number is also equal to the valency.

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Physical therapists, help harmed or sick individuals enhance their development and deal with their agony. These therapists are frequently an imperative piece of the restoration, treatment, and counteractive action of patients with unending conditions, ailments, or wounds.  

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7 0
3 years ago
Read 2 more answers
2) A common "rule of thumb" -- for many reactions around room temperature is that the
babunello [35]

The question is incomplete. The complete question is :

A common "rule of thumb" for many reactions around room temperature is that the rate will double for each ten degree increase in temperature. Does the reaction you have studied seem to obey this rule? (Hint: Use your activation energy to calculate the ratio of rate constants at 300 and 310 Kelvin.)

Solutions :

If we consider the activation energy to be constant for the increase in 10 K temperature. (i.e. 300 K → 310 K), then the rate of the reaction will increase. This happens because of the change in the rate constant that leads to the change in overall rate of reaction.

Let's take :

$T_1=300 \ K$

$T_2=310 \ K$

The rate constant = $K_1 \text{ and } K_2$ respectively.

The activation energy and the Arhenius factor is same.

So by the arhenius equation,

$K_1 = Ae^{-\frac{E_a}{RT_1}}$  and $K_2 = Ae^{-\frac{E_a}{RT_2}}$

$\Rightarrow \frac{K_1}{K_2}= \frac{e^{-\frac{E_a}{RT_1}}}{e^{-\frac{E_a}{RT_2}}} $

$\Rightarrow \frac{K_1}{K_2}=  e^{-\frac{E_a}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)}$

$\Rightarrow \ln \frac{K_1}{K_2}= - \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

Given, $E_a = 0.269$ J/mol

           R = 8.314 J/mol/K

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{0.269}{8.314} \left(\frac{1}{300} -\frac{1}{310} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{0.269}{8.314} \times \frac{10}{300 \times 310}$

$\Rightarrow \ln \frac{K_2}{K_1}=  3.479 \times 10^{-6}$

$\Rightarrow  \frac{K_2}{K_1}=  e^{3.479 \times 10^{-6}}$

$\Rightarrow  \frac{K_2}{K_1}=  1$

∴ $K_2=K_1$

So, no this reaction does not seem to follow the thumb rule as its activation energy is very low.

8 0
3 years ago
What element are usually shiny , can be bent or stretched and conduct electricity
Alik [6]

Answer:

gold and copper

Explanation:

but I think there is 1 more

8 0
3 years ago
Wich has a larger percent by mass of sulfur - H2SO or H2S7O8?
Pie

Answer:

Explanation:

H2SO4 let S be x

2(1) + x + 4(-2) = 0

2 + x - 8 = 0

x - 6 = 0

x = 6

For H2S7O8 let S be x

2(1) + 7(x) + 8(-2) = 0

2 + 7x - 16 = 0

7x - 14 = 0

7x = 14

x = 14/7

x = 2

:- H2SO4 as the larger percentage

5 0
3 years ago
What is the percent magnesium in a sample made of 24g Mg and 70gCl?
seropon [69]

Answer:

Total percent of magnesium in sample = 25.5%

Explanation:

Given:

Mass of magnesium = 24 gram

Mass of chlorine = 70 gram

Find:

Total percent of magnesium in sample = ?

Computation:

Total mass of sample = Mass of magnesium + Mass of chlorine

Total mass of sample = 24 gram + 70 gram

Total mass of sample = 94 gram

Total percent of magnesium in sample = [Mass of magnesium / Total mass of sample]100

Total percent of magnesium in sample = [24/94]100

Total percent of magnesium in sample = [0.255]100

Total percent of magnesium in sample = 25.5%

5 0
4 years ago
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