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Tems11 [23]
3 years ago
11

Addition of the indicator methyl orange to an unknown solution leads to a yellow color. The addition of bromthymol blue to the s

ame solution also leads to a yellow color. (a) Is the solution acidic, neutral, or basic?
Chemistry
1 answer:
malfutka [58]3 years ago
8 0

Answer: The solution is acidic.

Explanation:

You must find the behavior of the different indicators in the literature, for which you can use internet.

There you will find that <em>methyl orange</em> is useful to differentiate if a solution is <em>more acidic</em> (pH below 3.1) or <em>less acidic</em> (pH above 4.4).

In other words, when acidity in decreasing, i.e. the pH is increasing, the <em>methyl orange</em> indicator goes from red (more acidic) to yellow (less acidic).

So, as it is stated that the <em>addition of the indicator methyl orange to the unknown solution leads to a yellow color</em>, you just can tell that the pH is above 4.1, which means that the solution may be slightly acid, neutral or basic. In this case, the indicator methyl orange cannot help you to determine the answser.

So, you must move to the information regarding the other indicator (bromthymol blue) to try to infer whether the solution is <em>acidic, neutral, or basic</em>.

You can find in the literature that the indicator <em>bromthymol blue</em> leads<em> to a </em><em>yellow color in acidic solutions</em>, greenish in neutral solutions, and blue in basic solutions.

Since it is stated in the question that <em>the adition of bromthymol blue to the same solution also leads to a yellow color</em>, you can conclude that the solution is acidic.

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Answer:

Induction

Explanation:

When a body is brought in contact with another, electrons are rearranged by contact.

When a body is rubbed against one another, charging by friction occurs.

The process whereby electrons are rearranged without direct contact with one another is called induction.

By induction electrons can get charged without them having to be in contact with one another.

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Consider the chemical equation for the ionization of CH3NH2 in water. Estimate the percent ionization of CH3NH2 in a 0.050 M CH3
anyanavicka [17]

Answer:  The percent ionization of CH_3NH_2 in a 0.050 M CH_3NH_2(aq) solution is 8.9 %

Explanation:

CH_3NH_2+H_2O\rightarrow OH^-+CH_3NH_3^+

 cM                            0             0

c-c\alpha                       c\alpha            c\alpha

So dissociation constant will be:

K_b=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= concentration = 0.050 M and \alpha = degree of ionisation = ?

K_b=4.4\times 10^{-4}

Putting in the values we get:

4.4\times 10^{-4}=\frac{(0.050\times \alpha)^2}{(0.050-0.050\times \alpha)}

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percent ionisation =0.089\times 100=8.9\%

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Explanation:

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Since dimethyl ether is a nonpolar organic compound, then it has London forces as its major intermolecular force. Intermolecular forces hold molecules of a substance together in a given state of matter.

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