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3 years ago

What was the result of john Brown's raid on Harpers ferry

Chemistry

2 answers:

charle [14.2K]3 years ago

8 0

Answer:

The result was the death of 6 people, including the son of John Brown. In addition, 9 were injured and John Brown was captured and hanged.

Explanation:

John Brown joined the history books here in the USA because of his courageous act in which he along with a group of 21 people (15 whites and 6 blacks) perpetrated in Virgina (South) 150 years ago. On October 16, 1859, he and his followers attacked the federal arsenal of "Harpers Ferry." This attack was part of a grand plan to try to destroy the abominable system of slavery, liberating and also arming the slaves in the states of Georgia, North Carolina, South Carolina and Virginia. These states defended not only their autonomy before the federal government, but also the right to own slaves. The invaders were captured by the Army led by Robert E. Lee, future general in the war of the session by the confederate states. Mr. Brown who lost a child during the fight was hanged on December 2, 1859.

FrozenT [24]3 years ago

4 0

The result of john Brown's raid on Harpers ferry is that 6 people were killed, and 9 were wounded.

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3 years ago

When a student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, the temperature of the resultant so

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Answer: 54.4 kJ/mol

Explanation:

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$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.0\times 0.05L=0.05mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.05 mole of HCl neutralizes by 0.05 mole of NaOH

Thus, the number of neutralized moles = 0.05 mole

Now we have to calculate the mass of water:

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $50ml+50ml=100ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 100ml=100g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 100 g

$T_{final}$ = final temperature of water = $27.5^0C$

$T_{initial}$ = initial temperature of metal = $21.0^0C$

Now put all the given values in the above formula, we get:

$q=100g\times 4.18J/g^oC\times (27.5-21.0)^0C$

$q=2719.6J=2.72kJ$

Thus, the heat released during the neutralization = 2.72 KJ

Now we have to calculate the enthalpy of neutralization per mole of $HCl$ :

0.05 moles of $HCl$ releases heat = 2.72 KJ

1 mole of $HCl$ releases heat = $\frac{2.72}{0.05}\times 1=54.4KJ$

Thus the enthalpy change for the reaction in kJ per mol of HCl is 54.4 kJ

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skelet666 [1.2K]

Answer:

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Paul [167]

<h3>Answer:</h3>

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<h3>Explanation:</h3>

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