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VladimirAG [237]
2 years ago
12

Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12

to C-14 in the atmosphere is 1 x 1012. The table shows this ratio inside the body of three organisms.
C12/C14 Ratio
Organism C12/C14 Ratio
E 8 x 1012
F 1 x 1012
G 4 x 1012


What can most likely be concluded from the above information?
Only Organism F is alive, and Organism G died before Organism E.
Only Organism F is alive, and Organism E died before Organism G.
Only Organism E is alive, and Organism G died before Organism F.
Only Organism E is alive, and Organism F died before Organism G.
Chemistry
1 answer:
lidiya [134]2 years ago
5 0

Explanation:

The 3rd one is your answer

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Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid
bogdanovich [222]

Explanation:

Aqueous hydrobromic acid (HBr) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H₂O). They will react according to the following equation.

HBr + NaOH ---> NaBr + H₂O

0.81 g of HBr are mixed with 0.568 g of NaOH. We have to find the mass of NaBr that can be produced. To do that we have to find which of the reactants is limiting the reaction. First, we will convert their grams into moles using their molar masses.

molar mass of HBr = 80.91 g/mol

molar mass of NaOH = 40.00 g/mol

mass of HBr = 0.81 g

mass of NaOH = 0.568 g

moles of HBr = 0.81 g * 1 mol/(80.91 g)

moles of HBr = 0.0100 moles

moles of NaOH = 0.568 g * 1 mol/(40.00 g)

moles of NaOH = 0.0142 moles

HBr + NaOH ---> NaBr + H₂O

Now if we take a quick look at the coefficients of the reaction we will see that 1 mol of HBr will react with 1 mol of NaOH since both coefficients are 1. Then their molar ratio is 1 : 1. That also means that 0.0100 moles of HBr will only react with 0.0100 moles of NaOH, and we have mixed 0.0142 moles of it. So, NaOH is in excess and HBr is the limiting reagent.

1 mol of HBr : 1 mol of NaOH molar ratio

moles of NaOH = 0.0100 moles of HBr * 1 mol of NaOH/(1 mol of HBr)

moles of NaOH = 0.0100 moles < 0.0142 moles ----> NaOH is in excess

And now that we know that HBr is the limiting reagent we can find the number of moles of NaBr that will be produced by 0.0100 moles of HBr. And finally convert those moles into grams using the molar mass.

1 mol of HBr : 1 mol of NaBr molar ratio

moles of NaBr = 0.0100 moles of HBr * 1 mol of NaBr/(1 mol of HBr)

moles of NaBr = 0.0100 moles

molar mass of NaBr = 102.89 g/mol

mass of NaBr = 0.0100 moles * 102.89 g/mol

mass of NaBr = 1.0289 g

mass of NaBr = 1.0 g

Answer: the maximum mass of sodium bromide that could be produced is 1.0 g.

7 0
1 year ago
A larger glass has 100 mL of a liquid and a smaller glass has 50 mL of a liquid. Which glass of liquid would have more energy?
sukhopar [10]

Answer:Calculations must be done first because energy depends on both temperature and mass.

Explanation:

6 0
3 years ago
how do you tell if an element has positive or negative charge. And how do you know when the valence electrons have to be shared
Eva8 [605]

Answer:

A normal atom has a neutral charge. When you are missing electrons it has a positive charge. When you have extra electron, you have a negative charge. I am not sure what the answer to your second question is, sorry.

Explanation:

7 0
3 years ago
What is the relationship between frequency and velocity of a wave direct inverse or no relationship
Lostsunrise [7]

Answer:

For a constant wavelength, Increase in frequency will increase in velocity of the wave. Example: For a constant wavelength, If frequency is doubled. The velocity of the wave will also double.

Explanation:

7 0
3 years ago
What substance would you add to KF(aq) to form a buffer solution? View Available Hint(s) What substance would you add to to form
AnnyKZ [126]
<h3>Answer</h3>

HF

<h3>Explanation</h3>

A buffer solution contains <em>a weak acid</em> and<em> its conjugate base</em>. The two species shall have a similar concentration in the solution. It's also possible for <em>a weak base</em> and <em>its conjugate acid</em> to form a buffer solution.

The KF solution already contains large number of \text{F}^{-} ions. The objective is to thus find its conjugate acid or base.

\text{F}^{-} contains no proton \text{H}^{+} and is unlikely to be a conjugate acid. Assuming that \text{F}^{-} is a conjugate base. Adding one proton to \text{F}^{-} would produce its conjugate acid.

\text{H}^{+} \; (aq) + \text{F}^{-} \; (aq) \rightleftharpoons \text{HF}\; (aq)

Therefore \text{HF} is the conjugate acid of \text{F}^{-}. \text{HF} happens to be a weak acid. As a result, combining \text{F}^{-} with \text{HF} would produce a solution with large number of both the weak acid and its conjugate base, which is a buffer solution by definition.

4 0
3 years ago
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