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4 years ago

It is possible for a PowerPoint user to add notes to slides and see the added comments.

Physics

2 answers:

sp2606 [1]4 years ago

6 0

Answer:

True

Explanation:

Honestly it could be true or false, but I chose true, because I do power points all the time for projects and presentations and you can add notes on the side, but they only remain visable when you go back to it. If you go to type on the power point the note will disappear.

I hope that helps

Digiron [165]4 years ago

3 0

True because it true that you can I’m being forced to make this answer longer please help

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Explain in 2-3 sentences how a genotype determines a phenotype! <br> Will give b to the best one

allochka39001 [22]

Answer:

Genotype can be determined by biological tests. Both the genotype and phenotype sounds similar but have differences. The phenotype is determined by an individual’s genotype and expressed genes or by visible trait, for instance, hair color or type, eye color body shape, and height. We are all unique. Even monozygotic twins, who are genetically identical, always have some variation in the way they look and act. This uniqueness is a result of the interaction between our genetic make-up, inherited from our parents, and environmental influences from the moment we are conceived.

4 0

3 years ago

A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2

ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}$

And we need to find out the change in momentum of the body . Here ,

velocity before collision (u) = 10m/s
velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

$\sf\longrightarrow momentum (p)= mass(m) * velocity(v)$

Therefore change in momentum will be,

$\sf\longrightarrow \triangle p = mv - mu$

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

$\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\$

$\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s) \\$

$\sf\longrightarrow \Delta p = 0.1 kg * -12m/s \\$

$\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\$

7 0

2 years ago

An object will maintain a constant speed until a force acts on it true or false

Scorpion4ik [409]

<span>You do not require a force to keep something moving. You only require a force to get it moving. Or to stop it moving. In your everyday experiences, something you get moving seems to come to a stop after you stop pushing it. It is because there are forces (friction) that make it stop. Without those forces, the object would just keep moving. So this would mean the answer would be True.</span>

3 0

3 years ago

"A problem involves a car of mass m going down a track from a height H, and round a loop of radius r. The loop is frictionless.

neonofarm [45]

Answer:

Explanation:

At the topmost position, the car does not have zero velocity but it has velocity of v so that

v² /r = g or centripetal acceleration should be equal to g ( 9.8 )

Considering that, the car must fall from a height of 2r + h where

mgh = 1/2 mv²

= 1/2 m gr

So h = r/2

Hence the ball must fall from a height of

2r + r /2

= 2.5 r . So that it can provide velocity of v at the top where

v² / r = g .

4 0

3 years ago

how many days does it take a team of drivers to drive a truck california and back to lansing if the drivers average 15m/s includ

Scilla [17]

Answer:

t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]

Explanation:

First, we need to arrange the problem to work in the same unit system (SI).

We need to convert the 1800 [miles] to meters, therefore:

$1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km]$

Now using the following equation of kinematics, for the avarage velocity we have:

$v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\$

therefore:

$t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s]$

Now we can convert from seconds into days.

$193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\ t = 2.2[days]$

Now if the truck has the need to come back, the team will spend double time.

t= 4.4 [days]

4 0

3 years ago