Answer:
a)
b)
Explanation:
Let the first ball throw be the point of reference, we can have following the equation of motion:
1st ball: 
2nd ball: 
a)When the 2 balls collide they are at the same spot at the same time:




b) The first ball is at its highest point when v = 0. That is

After this time, the 2 balls would have traveled through a distance of


Since
we can solve for H

<h3><u>Answer;</u></h3>
B. the rotation of Earth on its axis
<h3><u>Explanation;</u></h3>
- <em><u>The Coriolis effect describes how the Earth's rotation steers winds and surface ocean currents. The Coriolis effect causes the motion of a freely moving object to appear as a curve.</u></em>
- <em><u>Therefore, since air and water move freely, the Coriolis effect makes their movement to be curved. This is why the movement of winds and oceans does not follow a straight line but it is bent and curved.</u></em>
Answer:
(a) T = 0.412s
(b) f = 2.42Hz
(c) w = 15.25 rad/s
(d) k = 86.75N/m
(e) vmax = 5.03 m/s
Explanation:
Given information:
m: mass of the block = 0.373kg
A: amplitude of oscillation = 22cm = 0.22m
T: period of oscillation = 0.412s
(a) The period is the time of one complete oscillation = 0.412s
The period is 0.412s
(b) The frequency is calculated by using the following formula:

The frequency is 2.42 Hz
(c) The angular frequency is:

The angular frequency is 15.25 rad/s
(d) The spring constant is calculated by solving the following equation for k:

The spring constant is 86.75N/m
(e) The maximum speed is:

(f) The maximum force applied by the spring if for the maximum elongation, that is, the amplitude:

The maximum force that the spring exerts on the block is 17.35N
Answer: velocity = 79.6m/s, distance covered = 139.6m and velocity when distance is 10.0m = 61.611m/s
Explanation:
First step is to take a direction of motion, so to avoid issues with negative sign, I take my direction of motion as the positive y axis which makes the parameters positive.
The object is of a free fall thus it has a constant acceleration of g = 9.8m/s².
a) initial velocity (u) = 60m/s, g = 9.8m/s², time taken (t) =2s, we need to get velocity at that time using the formulae below
v = u + at
v = 60 + (9.8)* 2
v = 60 + 19.6
v = 79.6m/s
b) to get the distance traveled at t =2s, we use the formulae below
s =ut + 1/2at² where s = distance covered.
s = 60 * 2 + 1/2 * 9.8 * 2²
s = 120 + 1/2 *9.8 * 4
s = 120 + 9.8 * 2
s = 120 + 19.6
s = 139.6m
c) to get the velocity (v) when distance traveled (s) = 10m, we use the formulae below.
v² = u² + 2as
v² = 60² + 2( 9.8)(10)
v² = 3600 + 196
v² = 3796
v = √3796
v = 61.611m