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2 years ago

the sun is one hundred and fifty million kilometers away from earth write this in scientific notation

Physics

1 answer:

Viefleur [7K]2 years ago

6 0

Answer: its 15 i think i hope this helps

Explanation:

As an example, the distance from Earth to the Sun is about 150,000,000,000 meters – a very large distance indeed. In scientific notation, the distance is written as 1.5 × 1011 m.

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A box of bananas weighing 40.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surfa

Burka [1]

Answer:

(a) = 0 N

(b) = 2.4 N

Explanation:

given

box of banana weight = 40.0 N

coefficient of static friction μ = 0.40

coefficient of kinetic friction = 0.20

a). when no horizontal force is applied .

according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N

b) magnitude of friction force

box and the box is initially at rest

friction force =.Static friction coefficient × weight of the box

friction force = 0.40 × 6

friction force = 2.4 N

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3 years ago

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Answer:

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3 years ago

Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of

STatiana [176]

Answer:

$2.27\cdot 10^{49}$

Explanation:

The gravitational force between the proton and the electron is given by

$F_G=G\frac{m_p m_e}{r^2}$

where

G is the gravitational constant

$m_p$ is the proton mass

$m_e$ is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N$

The electrical force between the proton and the electron is given by

$F_E=k\frac{q_p q_e}{r^2}$

where

k is the Coulomb constant

$q_p = q_e = q$ is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N$

So, the ratio of the electrical force to the gravitational force is

$\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}$

So, we see that the electrical force is much larger than the gravitational force.

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Tasya [4]

I believe the answer is free electrons

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4 years ago

the sun is one hundred and fifty million kilometers away from earth write this in scientific notation​

the sun is one hundred and fifty million kilometers away from earth write this in scientific notation