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Vladimir79 [104]
3 years ago
6

Which of these statements describes what occurs in facilitated diffusion?-Facilitated diffusion requires energy from the cell to

drive a concentration gradient.-Facilitated diffusion of solutes occurs through protein pores in the membrane.-Facilitated diffusion of solutes occurs through phospholipid pores in the membrane.-Facilitated diffusion is another name for osmosis.
Physics
1 answer:
Softa [21]3 years ago
6 0

Answer:

Facilitated diffusion of solutes occurs through protein pores in the membrane.

Explanation:

Facilitated diffusion: It is known as a type a passive transport which diffuses the solutes through specific trans membrane integral proteins in the plasma membrane. Transport proteins helps in diffuse some ions, and molecules across the plasma membrane.

There are three types of transport proteins which are involved in this diffusion:

1) gated channel proteins.

2) carrier proteins.

3) channel proteins.

Some example of facilitated diffusion are: glucose transporter, ion channels, and aquaporins.

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A ball is dropped off the side of a bridge.<br> After 1.55 s, how far has it fallen?
KengaRu [80]

Answer:11.7 meters

Explanation: Gravitational acceleration (g)

9.8 m/s²

Initial velocity (v₀)

0 ft/s

Height (h)

11.77225 m

Time of fall (t)

1.55 sec

Velocity (v)

15.19 m/s

6 0
3 years ago
A ring, cylinder, solid sphere, and hollow sphere are all released from rest from the same height on an inclined surface, at the
crimeas [40]

Answer:

Explanation:

  • The expression for acceleration of the rolling body on an inclined plane is given as a = gsinФ/1 + k²/R²
  • where Ф is the angle of inclination, R is the radius, k is the radius of gyration.
  • The potential energy of the system is given as ; PE = mgh
  • The potential energy will be constant for ring, cylinder, solid sphere, and hollow sphere.
  • The total kinetic energy of the rolling body is ; KE = mv²/2 + Iw²/2
  • Hence, the total kinetic energy of the ring, cylinder, solid sphere and hollow sphere will be constant.

2. The moment of inertia of the ring is given as ;

I = mR²

The moment of inertia of the ring is maximum and therefore reaches the bottom last.

7 0
3 years ago
A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
tigry1 [53]

Explanation:

Given that,

Mass if the rock, m = 1 kg

It is  suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.

We need to find the mass of the meter stick. The force acting by the stone is

F = 1 × 9.8 = 9.8 N

Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

W = 3.266 N

The mass of the meters stick is :

m=\dfrac{W}{g}\\\\m=\dfrac{3.266}{9.81}\\\\m=0.333\ kg

So, the mass of the meter stick is 0.333 kg.

5 0
3 years ago
f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t
inysia [295]

Answer:

The velocity of the arrow after 3 seconds is 30.02 m/s.

Explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

h(t)=35t-0.83t^2

We know that the rate of change of displacement is equal to the velocity of an object.

v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t

Velocity of the arrow after 3 seconds will be :

v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

7 0
3 years ago
How fast is a 90kg man running if his kinetic energy is 720 J?
zheka24 [161]
Answer:
4 m/s
Explanation:
KE=1/2mv^2
720=1/2(90)
720=45v^2
divide by 45
16= v^2
over the square root
4=v
v= 4m/s
6 0
3 years ago
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