Answer:
the force of attraction between the two charges is 4.2 x 10⁹ N.
Explanation:
Given;
the magnitude of first charge, q₁ = 0.06 C
the magnitude of the second charge, q₂ = 0.07 C
distance between the two charges, r = 3 m
The force of attraction between the two charges is calculated as ;

where;
k is Coulomb's constant = 9 x 10⁹ Nm²/C²

Therefore, the force of attraction between the two charges is 4.2 x 10⁹ N.
Hey here is your answer u r looking for
24.041m
The moon has approximately 1/4 of earths diameter, 1/50 of earths volume and 1/80 of earths mass
Answer:
0.4A.
Explanation:
Current (A) = Charge (coulomb)/Time (secs)
2 coulombs/5 secs = 0.4A