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Sonbull [250]
3 years ago
15

Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.1 g. Silver has 47 electrons

per atom, and its molar mass is 107.87 g/mole.
Physics
1 answer:
Assoli18 [71]3 years ago
7 0

<u>Answer:</u> The number of electrons in given amount of silver are 1.87\times 10^{24}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of silver = 7.1 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol

Number of electrons in 1 atom of silver = 47

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of particles

So, 0.066 moles of silver will contain = -(0.066\times 47\times 6.022\times 10^{23})=1.87\times 10^{24} number of electrons

Hence, the number of electrons in given amount of silver are 1.87\times 10^{24}

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4.5g/cm^3

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Here, Mass(m)=67.5g

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