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Allisa [31]
3 years ago
8

As altitude increases, atmospheric pressure decreases, which means less oxygen is diffused into the blood from the lungs. for in

stance, at 18,000 feet you would obtain 29% less oxygen than you would at sea level. this can lead to altitude sickness, or hypoxia as it is called. imagine a mountain climber, who lives at sea level, trying to climb mount kilimanjaro for the first time. the climber is very fit so he plans to summit the 19,341 foot peak in four days, though it usually takes first-time climbers five or six days. use your knowledge of equilibrium to predict the climberâs reaction to this speedy climb, and the reaction needed to restore equilibrium.
Physics
2 answers:
Anni [7]3 years ago
8 0

 

I believe this question has the following sub questions:

1. When the climber ascends the mountain before acclimating, ___ to restore homeostasis within the body. <span>
2. As the climber rehydrates and rests at a basecamp, hemoglobin (Hb) is produced, which is the body's response to the stress. As a result, ___ </span>
3. When the climber returns to sea level before reacclimating, ___ to restore homeostasis within the body. 
4. As the climber reacclimates to sea level, hemoglobin is replaced at a lower rate, decreasing hemoglobin concentrations in the blood. As a result, ___

 

The answers on each sub question are:

1) Equilibrium shifts to release O2<span>
<span>2) Equilibrium shifts to formation of HbO2</span>
<span>3) Equilibrium shifts to formation of HbO2</span>
<span>4) Equilibrium shifts to release O2</span></span>

Elina [12.6K]3 years ago
5 0

Question subitems:

1. When the climber ascends the mountain before acclimating, __to restore homeostasis within the body.

2. As the climber rehydrates and rests at a basecamp, hemoglobin (Hb) is produced, which is the body's response to the stress. As a result, __

3. When the climber returns to sea level before reacclimating, __ to restore homeostasis within the body.

4. As the climber reacclimates to sea level, hemoglobin is replaced at a lower rate, decreasing hemoglobin concentrations in the blood. As a result, __

Explanation:

1) The body will try to compensate the concentration of oxygen so the equilibrium will shift to release O2

2) The body will try to restore the ammount of oxygen in blood so it will producec Hb and shift to the production of HbO2

3) The higher oxygen concentration will trend to increase the formation of HbO2

4) To restorre the homeostasis the equilibrium will shift to the release of O2

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What does more damage; a slow semi truck, or a fast sports car
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An object of mass 25kg is falling from the height h=10 m. calculate
r-ruslan [8.4K]

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

Explanation:

V²=U²+2gh

V²=0 + 2×10×10=200m/s

a).kinetic energy=(1/2)mv²=(1/2)25×200=2500

potential energy=mgh

p.e=25×10×10=2500J

pe+ke=2500+2500=5KJ

b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

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kinetic energy=(1/2)mv²

=(1/2)25×80

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6 0
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Jan first uses a Michelson interferometer with the 606 nmnm light from a krypton-86 lamp. He displaces the movable mirror away f
gogolik [260]

Answer:

a) d₁ = 247.8 μm

d₂ = 205.3 μm

b) d₂ = 20.53 x 10⁻⁵ m = 205.3 μm

Explanation:

a)

The formula for Michelson Interferometer is derived to be:

d = mλ/2

where,

d = distance moved

m = no. of fringes

λ = wavelength of light

For JAN, we have following data

d = d₁

m = 818

λ = 606 nm = 606 x 10⁻⁹ m

Therefore,

d₁ = (818)(606 x 10⁻⁹ m)/2

<u>d₁ = 24.78 x 10⁻⁵ m = 247.8 μm</u>

For LINDA, we have following data

d = d₂

m = 818

λ = 502 nm = 502 x 10⁻⁹ m

Therefore,

d₂ = (818)(502 x 10⁻⁹ m)/2

<u>d₂ = 20.53 x 10⁻⁵ m = 205.3 μm</u>

b)

The resultant displacement can be found out from the difference between both displacement. And the direction of resultant displacement will be the same as the direction of greater displacement. Therefore,

Resultant Displacement = Δd = d₁ - d₂

Δd = 247.8 μm - 205.3 μm

<u>Δd = 42.5 μm (in the direction of JAN)</u>

4 0
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