Answer:
So the force of attraction between the two objects is 3.3365*10^-6
Explanation:
m1=10kg
m2=50kg
d=10cm=0.1m
G=6.673*10^-11Nm^2kg^2
We have to find the force of attraction between them
F=Gm1m2/d^2
F=6.673*10^-11*10*50/0.1^2
F=3.3365*10^-8/0.01
F=3.3365*10^-6
Your answer will be Radio Waves .
That seems to be the only to make sense. Hope that helps u
Answer:
50.3N
Explanation:
Work done = force x distance
422J. = force x 8.39m
÷8.39 both side to get force
Force is 50.3N to 1 d.p.
Check:
50.3 x 8.39=422.017J
Same as 422J to 1 d.p
Incomplete question as number of moles and length is missing.So I have assumed 3 moles and length of 0.300 m.So the complete question is here:
Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m.What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?
Answer:
The Force act on each side is 2.43×10⁴N
Explanation:
Given data
n=3 mol
L=0.3 m
Temperature=20.0°C=293 K
To find
Force F
Solution
To get force act on each side it would employ by
F=P.A
Where P is pressure
A is Area
First we need to find pressure by applying ideal gas law
So

So The Force is given as:

The Force act on each side is 2.43×10⁴N
Answer: Share
Explanation: <em>A mixture in which its constituents are distributed uniformly is called homogeneous mixture, such as salt in water. A mixture in which its constituents are not distributed uniformly is called heterogeneous mixture, such as sand in water.</em>