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juin [17]
3 years ago
6

A grindstone of radius 4.0 m is initially spinning with an angular speed of 8.0 rad/s. The angular speed is then increased to 12

rad/s over the next 4.0 seconds. Assume that the angular acceleration is constant.What is the magnitude of the angular acceleration of the grindstone?
Physics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

1 rad/s^2

Explanation:

The magnitude of the constant angular acceleration is the change in angular velocity over a unit of time. So if the angular speed increases from 8 rad/s to 12 rad/s in 4 seconds then the angular acceleration is:

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{12 - 8}{4} = \frac{4}{4} = 1 rad/s^2

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Pls help :(( I need help!! Its physics! motion and forces!
Delvig [45]

Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.

The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.

Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.

8 0
3 years ago
How does the speed of the different molecules that make up the air depend on their masses?
koban [17]
Larger molecules will move slower and smaller molecules will move faster. Did this answer your question?

8 0
3 years ago
For the circuit in the previous part, what happens to the maximum current if the frequency is doubled and the inductance is halv
tamaranim1 [39]

Answer:

Following are the responses to these question:

Explanation:

Since the max^{m} is the current of ckt which depend on the reactance which   inductor that also enables the ckt and inductor resistance (X_L) for capacities

\to X_{C}=\frac{1}{W L}

for

\to X_{L}=wL

When w \longrightarrow 2w

L\longrightarrow \frac{L}{2}

then

\to X_{L}=2 w \times \frac{L}{2}=wL

 therefore, X_{L} remains at the same so, the maximum current remains the in same ckt.

4 0
3 years ago
In a pendulum system, when is it possible for the potential and kinetic energies both to be equal to zero
muminat
That's ONLY true when the pendulum is hanging
in the center position and not moving.
8 0
4 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
Read 2 more answers
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