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juin [17]
3 years ago
6

A grindstone of radius 4.0 m is initially spinning with an angular speed of 8.0 rad/s. The angular speed is then increased to 12

rad/s over the next 4.0 seconds. Assume that the angular acceleration is constant.What is the magnitude of the angular acceleration of the grindstone?
Physics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

1 rad/s^2

Explanation:

The magnitude of the constant angular acceleration is the change in angular velocity over a unit of time. So if the angular speed increases from 8 rad/s to 12 rad/s in 4 seconds then the angular acceleration is:

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{12 - 8}{4} = \frac{4}{4} = 1 rad/s^2

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8 0
10 months ago
What is the magnitude of electrical force of attraction between an copper nucleus (29 protons) and its innermost electron if the
Agata [3.3K]
The charge of the copper nucleus is 29 times the charge of one proton:
Q=29 q= 29 \cdot 1.6 \cdot 10^{-19}C=4.64 \cdot 10^{-18}C
the charge of the electron is
e=-1.6 \cdot 10^{-19}C
and their separation is
r=1.0 \cdot 10^{-12} m

The magnitude of the electrostatic force between them is given by:
F=k_e  \frac{Qe}{r^2}
where k_e is the Coulomb's constant. If we substitute the numbers, we find (we can ignore the negative sign of the electron charge, since we are interested only in the magnitude of the force)
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(4.64 \cdot 10^{-18}C)(1.6 \cdot 10^{-19}C)}{(1.0 \cdot 10^{-12} m)^2}=6.68 \cdot 10^{-3} N
3 0
3 years ago
What is the starting and final energy for a battery?
EleoNora [17]
Electrical energy is the starting and final energy of a battery
8 0
2 years ago
1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es
bezimeni [28]

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

7 0
2 years ago
Would it be m/s or kg?
Nesterboy [21]

Answer:

m.s

Explanation:

3 0
2 years ago
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