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Elena-2011 [213]
3 years ago
9

Why is my lawn mower not starting?

Engineering
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

Other possible causes include: Loose, Dirty or Disconnected Spark Plug in Your Lawn Mower: Check it out, clean off debris, re-connect and tighten. Dirty Air Filter: Clean or replace. Fuel Not Reaching the Engine: Tap the side of the carburetor to help the flow of gas.

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El tiempo hasta que falle un sistema informático sigue una distribución Exponencial con media de 600hs. (Utilice 3 decimales par
Lesechka [4]

Answer:

La probabilidad pedida es 0.717

Explanation:

Primero comencemos definiendo la variable aleatoria. Para nuestro problema, la variable aleatoria es la siguiente :

X: '' El tiempo (en horas) hasta que falle un sistema informático ''

La variable aleatoria X será entonces una variable aleatoria continua.

Sabemos que sigue una distribución exponencial con una media de 600 hs.

Esto se escribe :

X ~ ε ( λ ) (I)

En donde λ es igual a la inversa de la media. Esto se escribe :

λ =\frac{1}{E(X)}

En donde E(X) es la media de la variable. Por ende, si reemplazamos los datos del ejercicio obtenemos ⇒

λ =\frac{1}{E(X)} ⇒ λ =\frac{1}{600}

Si reemplazamos el valor de λ en (I) obtenemos :

X ~ ε (\frac{1}{600})

La función de distribución de X (por ser una variable aleatoria exponencial) es :

F_{X}(x)=P(X\leq x)=  1 - e ^ ( - λx) con x > 0 y F_{X}(x)=0 en caso contrario.

Si reemplazamos el valor de λ en la función de distribución de X obtenemos :

F_{X}(x)=P(X\leq x)=1-e^{-\frac{x}{600}}  

Dado que la variable aleatoria X se distribuye de manera exponencial, el hecho de saber que el sistema ha estado funcionando sin fallas durante 400 hs no nos aporta ninguna información sobre lo que ocurrirá después. Esta característica se conoce como propiedad de perdida de memoria de la variable aleatoria exponencial. Entonces, la probabilidad pedida se reduce a calcular :

P(X>200)    

Dado que saber que el sistema ha estado funcionando sin fallas durante 400 hs no nos dice nada sobre lo que ocurrirá instantes posteriores a esas 400 hs.

Calculamos entonces la probabilidad pedida :

P(X>200)=1-P(X\leq 200)=1-F_{X}(200)=1-(1-e^{-\frac{200}{600}})=e^{-\frac{1}{3}}=0.717

7 0
3 years ago
50 points what shape is mars
Artyom0805 [142]
A sphere.............
5 0
3 years ago
Read 2 more answers
Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of 11.0 mm. A tensile force of 1550 N produ
Natasha_Volkova [10]

Answer:

See it in the pic.

Explanation:

See it in the pic.

6 0
3 years ago
One of the best ways to avoid weather-induced hazards is to _____.
Sholpan [36]

Answer:

avoid them by choosing not to drive if you expect severe weather.

7 0
4 years ago
Please calculate the energy stored in a flying wheel. The steel flying wheel is 10 metric tons, in adiameter of 10m, and it rota
Liono4ka [1.6K]

Answer:

685.38 MJ

Explanation:

Given that:

mass = 10 tons = 1.0 × 10 ⁴ kg

diameter D = 10 m

radius R = 5 m

speed N = 1000 rpm

Using the formula for K.E = \dfrac{1}{2}I \omega^2 to calculate the energy stored

where;

= \dfrac{2 \pi \times N}{60}

= \dfrac{2 \pi \times 1000}{60}

= 104.719 rad/s

Hence, the energy stored is;

= \dfrac{1}{2}\times (\dfrac{MR^2}{2}) \times \omega^2

= \dfrac{1}{2}\times (\dfrac{10^4\times 5^2}{2}) \times 104.719^2

= 685379310.1

= 685.38 MJ

8 0
3 years ago
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