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Elena-2011 [213]

3 years ago

9

Why is my lawn mower not starting?

1 answer:

EleoNora [17]3 years ago

6 0

Answer:

Other possible causes include: Loose, Dirty or Disconnected Spark Plug in Your Lawn Mower: Check it out, clean off debris, re-connect and tighten. Dirty Air Filter: Clean or replace. Fuel Not Reaching the Engine: Tap the side of the carburetor to help the flow of gas.

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Generally natural shape of stone is in shaped as (a)angular (b)irregular (c)cubical cone shape (d)regular

Rudiy27

Option B. Did i helped?

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3 years ago

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Which statement most accurately describes Pascal's law?

marin [14]

Answer:

La C

Explanation:

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2 years ago

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Which of the following activities will allow an engineer to determine that a building's design is sound?

zhannawk [14.2K]

Please add more details because I don’t know if you are using a book or passage, therefore I cannot help you unless you add more detail

3 0

3 years ago

Suppose we have a database for an investment firm, consisting of the following attributes: B (broker), O (office of a broker), I

Snowcat [4.5K]

Answer:

Given, FDs are:

S -> D

I -> B

IS -> Q

B -> O

a)

"I" and "S" must be there in any candidate key because they do not appear on the right side of any functional dependency.

The only candidate key is: IS

IS -> ISBDQO

b)

Decomposition of R into 3NF: (I, B), (S, D), (B, O), (I, S, Q)

c)

Decomposition of R into BCNF:

Decompose R by I → B into R1 = (I, B) and R2 = (I, O, S, Q, D).

R1 is in BCNF

Decompose R2 by S → D into R21 = (S, D) and R22 = (O, I, S, Q).

R21is in BCNF

Decompose R22 by I → O into R221 = (I, O) and R222 = (I, S, Q).

R221 is in BCNF.

R222 is in BCNF.

The decomposition is: (I, B), (S, D), (I, O), (I, S, Q)

We can also write it as: (I, B), (S, D), (B, O), (I, S, Q)

Explanation:

The answer above is rendered in a very explanatory way.

8 0

2 years ago

A 4.4 HP electric motor spins a shaft at 2329 rpm. Find: The torque load carried by the shaft is closest to: Select one: a)-27.0

harina [27]

Answer:

Load carried by shaft=9.92 ft-lb

Explanation:

Given: Power P=4.4 HP

P=3281.08 W

<u><em>Power: </em></u>Rate of change of work with respect to time is called power.

We know that P= $Torque\times speed$

$\omega=\frac{2\pi N}{60}$ rad/sec

So that P= $\dfrac{2\pi NT}{60}$

So 3281.08= $\dfrac{2\pi \times 2329\times T}{60}$

T=13.45 N-m (1 N-m=0.737 ft-lb)

So T=9.92 ft-lb.

Load carried by shaft=9.92 ft-lb

3 0

2 years ago