Question

A tensile-testing machine is to test specimens of diameter 15 mm which have ultimate tensile strengths of up to 820 N/mm2. What is the maximum tensile force the machine must be capable of?

Answer 1

Answer:

14.48 N

Explanation:

We have given the diameter of the specimens d = 15 mm ,so radius $r=\frac{15}{2}=7.5 cm$

Area of the specimen $A=\pi r^2=3.14\times 0.075^2=0.01766m^2$

The maximum tensile strength = 820 $N/m^2$

We know that $maximu\ tensile\ strength =\frac{maximum\ tensile\ force}{Area}$

$820=\frac{maximu\ tensile\ force}{0.01766}=14.48N$