Answer:
Please explain it in English so that i can help you or you need someone who can speak Vietnam help you
Answer:
sorry im answering questions for the points cuz im built dfferent
Explanation:
Row choice the cost of roadway improvements to the developer and functional the amount of trafficBeing generated by the theater as well as the Ralph’s ladies
The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
<h3>
Thickness of the aluminum</h3>
The thickness of the aluminum can be determined using from distance of closest approach of the particle.
![K.E = \frac{2KZe^2}{r}](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7Br%7D)
where;
- Z is the atomic number of aluminium = 13
- e is charge
- r is distance of closest approach = thickness of aluminium
- k is Coulomb's constant = 9 x 10⁹ Nm²/C²
<h3>For 2.5 MeV electrons</h3>
![r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7BK.E%7D%20%5C%5C%5C%5Cr%20%3D%20%5Cfrac%7B2%20%5Ctimes%209%5Ctimes%2010%5E9%20%5Ctimes%2013%5Ctimes%20%281.6%5Ctimes%2010%5E%7B-19%7D%29%5E2%7D%7B2.5%20%5Ctimes%2010%5E6%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%7D%20%5C%5C%5C%5Cr%20%3D%201.5%20%5Ctimes%2010%5E%7B-14%7D%20%5C%20m)
<h3>For 2.5 MeV protons</h3>
Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.
<h3>For 10 MeV alpha-particles</h3>
Charge of alpah particle = 2e
![r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B2KZe%5E2%7D%7BK.E%7D%20%5C%5C%5C%5Cr%20%3D%20%5Cfrac%7B2%20%5Ctimes%209%5Ctimes%2010%5E9%20%5Ctimes%2013%5Ctimes%20%282%20%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%29%5E2%7D%7B10%20%5Ctimes%2010%5E6%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%7D%20%5C%5C%5C%5Cr%20%3D%201.5%20%5Ctimes%2010%5E%7B-14%7D%20%5C%20m)
Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.
Learn more about closest distance of approach here: brainly.com/question/6426420
Answer:
the elevation at point X is 2152.72 ft
Explanation:
given data
elev = 2156.77 ft
BS = 2.67 ft
FS = 6.72 ft
solution
first we get here height of instrument that is
H.I = elev + BS ..............1
put here value
H.I = 2156.77 ft + 2.67 ft
H.I = 2159.44 ft
and
Elevation at point (x) will be
point (x) = H.I - FS .............2
point (x) = 2159.44 ft - 6.72 ft
point (x) = 2152.72 ft