The kinetics formula that applies to this problem is
1. To find height, we use 1/2mv12−mg∗μ∗h sin θ = mgh where μ is equal to 0.20, v is 11 m/s and <span>θ is 40 degrees. we cancel mass, h is equal to 5.47 meters.
2. The final speed is from 2(ug</span>) * h sin <span>θ </span><span> = vf2
</span>2(0.2*9.8) * <span>sin 40 * 5.47= vf2 ; vf is equal to 3.71 m/s.
</span><span>
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1 Ampere
Explanation:
1/R = 1/8 + 1/10 + 1/12
1/R = (30 + 24 + 20) / 240
1/R = 74 / 240
R = 240 / 37
R = 120/37 Ohms
We know that,
V = IR
I = V/R
I = 12 / (120/37)
I = 12 × 37/120
I = 37/10
I = 3.7 A
Now,
The current in 12 ohm resistor →
= 1 A
∴ The current in 12 ohm resistor is 1 ampere
Your answer should be <span>wavelength</span>
Using the equation KE=1/2mv^2, plug in the numbers and solve for KE
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