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shutvik [7]
2 years ago
7

What is current of 12 ohm? help me pleasee​

Physics
1 answer:
worty [1.4K]2 years ago
3 0
1 Ampere

Explanation:

1/R = 1/8 + 1/10 + 1/12
1/R = (30 + 24 + 20) / 240
1/R = 74 / 240
R = 240 / 37
R = 120/37 Ohms
We know that,
V = IR
I = V/R
I = 12 / (120/37)
I = 12 × 37/120
I = 37/10
I = 3.7 A
Now,
The current in 12 ohm resistor →
= 1 A
∴ The current in 12 ohm resistor is​ 1 ampere
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One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (cre
elixir [45]

Answer:

wavelength.

Explanation:

One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (crest) and lowest (trough) points, and returning to the same value as the starting point is called a is called wavelength. Its can be also defined as the distance between two successive crests or trough points in wave form.

4 0
3 years ago
What is the final velocity, in m/s, of a hoop that rolls without slipping down a 8.20 m high hill, starting from rest?
pantera1 [17]

Answer:

12.68 m/s.

Explanation:

Equations of motion:

i. S = vi*t + 1/2 * a*(t^2)

ii. vf = vi + a*t

iii. vf^2 = vi^2 + 2a*S

Where, vf = final velocity

vi = initial velocity

S = distance travelled

a = acceleration due to gravity

t = time taken

Given:

vi = 0 m/s

S = 8.2 m

vf = ?

a = 9.81 m/s^2

Using iii. Equation of motion,

vf^2 = vi^2 + 2a*S

= 2 * 9.81 * 8.2

= 160.884

vf = sqrt (160.884)

= 12.68 m/s.

8 0
3 years ago
I’m tryna pass this class so pleaseee
Y_Kistochka [10]

Answer:

By looking at the graph it looks like its decreasing but you may want to re- read  the question to make sure that I am correct.I hope that this helps!

Explanation:

6 0
4 years ago
What two factors determine the density of a fluid?
tekilochka [14]

Answer:

Mass and volume.

Explanation:

The equation for density is always mass divided by volume. To determine the density of a fluid, you would need to find its volume and its mass.

6 0
4 years ago
Two parallel plates, each of area 3.37 cm2, are separated by 5.40 mm. The space between the plates is filled with air. A voltage
baherus [9]

Answer:

1, 1583.33 V/m

2, 4.72*10^-12 C

3, 39.2*10^-11 C

Explanation:

1

E = V / d

E = 8.55 / 5.4*10^-3

E = 8.55 / 0.0054

E = 1583.33 V/m

2

Capacitance, C = (k * e0 * A) / d, where k = 1

A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²

d = plate separation, 5.4 mm

e0 = Constant, 8.85*10^-12

Applying these, we have

C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 29.82*10^-16 / 0.0054

C = 5.52*10^-13 F

Since Q = CV, then

Q = 5.52*10^-13 * 8.55

Q = 4.72*10^-12 C

3

We are given that k = 83, so

Capacitance, C = (k * e0 * A) / d

C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 2.475*10^-13 / 0.0054

C = 4.58*10^-11 F

Q = CV

Q = 4.58*10^-11 * 8.55

Q = 39.2*10^-11 C

5 0
3 years ago
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