a spring length of 20cm, the vibrational frequency of the spring is 15 Hz, about that spring period is?
1 answer:
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(a)
The tangential acceleration component of the car is simply equal to the change of the tangential speed divided by the time taken:
This rate of change is already given by the problem, 0.800 m/s^2, so the tangential acceleration of the car is
(b)
The centripetal acceleration component is given by
where
v is the tangential speed
r is the radius of the trajectory
When the speed is v = 3.00 m/s, the centripetal acceleration is (the radius is r = 10.0 m):
(c)
The centripetal acceleration and the tangential acceleration are perpendicular to each other, so the magnitude of the total acceleration can be found by using Pythagorean's theorem:
and the direction is given by:
where the angle is measured with respect to the direction of the tangential acceleration.