Newton’s ______ law states that an object in motion stays in motion unless an unbalanced force acts on that object.

Identify the correct sequence for the formation and use of coal.

Zanzabum

The correct answer is - A. Plants store solar energy; the plants die; the plants are compressed; solar energy is released;

The plants use the solar energy for their functioning, thus they are one of the biggest natural storage of it. The plants also use the CO2 for the process of photosynthesis that is driven by the solar energy. When the plants die, the things inside them are stored in them, and if they are quickly covered they will remain stored and not get back into the atmosphere. The plants than are compressed, and over time that leads to a change in their composition. After millions of years had passed, the solar energy and CO2 had turned into coal. The coal is heavily used by the humans in the past few centuries, and with its burning the solar energy and the CO2 are released back into the atmosphere from which they came millions of years ago.

5 0

2 years ago

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The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. The distance between the

Mama L [17]

Answer: (a) power output = 3.85×10²⁶W

(b). There is no relative change in power as it is independent from frequency

(c). 590 W/m²

Explanation:

given Radius between earth and sun to be = 1.50 × 10¹¹m

Intensity of the radiation from the sun measured on earth to be = 1360 W/m²

Frequency = 60 MHz

(a). surface area A of the sun on earth is = 4πR²

substituting value of R;

A = 4π(.50 × 10¹¹)² = 2.863 10²³×m²

A = 2.863 10²³×m²

now to get the power output of the sun we have;

P sun = I sun-earth A sun-earth

where A = 2.863 10²³×m², and I  is 1360 W/m²

P sun = 2.863 10²³ × 1360

P sun = 3.85×10²⁶W

(c). surface area A of the sun on mars is = 4πR²

now we substitute value of 2.28 ×10¹¹ for R sun-mars, we have

A sun-mars = 4π(2.28× 10¹¹)²

A sun-mars = 6.53 × 10²³m²

now to calculate the intensity of the sun;

I sun-mars = P sun / A sun-mars

where P sun = 3.85×10²⁶W and A sun-mars = 6.53 × 10²³m²

I sun-mars = 3.85×10²⁶W / 6.53 × 10²³m²

I sun-mars = 589.6 ≈ 590 W/m²

I sun-mars = 590 W/m²

6 0

2 years ago

What is a volcanically active area that is not near a tectonic plate boundary?

belka [17]

It a blue tectonic movement

8 0

2 years ago

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri

Orlov [11]

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$ .

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5 m

Therefore, distance traveled is 162.5 m.

3 0

2 years ago

A 0.145 kg baseball is flying at a height of 2.50 m. How much potential energy

Studentka2010 [4]

Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:

$\boxed{U_g=W\cdot h=mgh}$

Where:

W is the weight of the object
m is the mass
g is gravitational acceleration
h is the height

Evaluating:

$U_g = (0.145\;kg)(9.8\;m/s^2)(2.50\;m)\\\\\boxed{U_g=3.5525\;J}$

R/ The ball has 3.5525 J of potential energy.

3 0

2 years ago