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3 years ago

Newton’s ______ law states that an object in motion stays in motion unless an unbalanced force acts on that object.

Physics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

First law of motion states that

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To meet the productivity goal, you must move 75 units of product per hour. You have moved 30 units of product in 30 minutes. How

9966 [12]

Answer:

1.5 unit of product per min

Explanation:

30 units of product was moved in 30 minutes.

Number of units left = Total number of units-number of units moved

=75-30 =45 units

45 units is available to be moved for the rest 30 min. To be able to achieve this goal of 75 units of product per hour.

45/30 amount of units must be moved in 1 min

=1.5 unit per min

4 0

3 years ago

A spaceship accelerates from 0m/s to 40m/s in 5 seconds. What is the acceleration of the spaceship

nadya68 [22]

Acceleration = change in velocity/time
= 40/5
=8m/s^2

6 0

3 years ago

What is the condition to earths atmosphere at a givin time and pace

alina1380 [7]

The condition of earths atmosphere at a given time and place is the weather.

6 0

3 years ago

An elephant lifts 7 large logs from the ground to a container 5 meters above the ground as part of a zoo demonstration. The elep

Alisiya [41]

The work done by the elephant to lift one log is the force multiplied by the height at which the log has been lifted:
$W=Fh=250 N \cdot 5 m=1250 J$
And so, the total work done to lift the 7 logs is 7 times the work done to lift each log:
$W_t = 7 W=7 \cdot 1250 N=8750 J$

5 0

3 years ago

A diver 40 m deep in 10 degrees C fresh water exhales a 1.5 cm diameter bubble.

zzz [600]

Answer:

0.0257259766982 m

Explanation:

$P_2$ = Atmospheric pressure = 101325 Pa

$d_1$ = Initial diameter = 1.5 cm

$d_2$ = Final diameter

$\rho$ = Density of water = 1000 kg/m³

h = Depth = 40 m

The pressure is

$P_1=P_2+\rho gh\\\Rightarrow P_1=101325+1000\times 9.81\times 40\\\Rightarrow P_1=493725\ Pa$

From ideal gas law we have

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow \dfrac{P_1\dfrac{4}{3\times8}\pi d_1^3}{T_1}=\dfrac{P_2\dfrac{4}{3\times8}\pi d_2^3}{T_2}\\\Rightarrow \dfrac{P_1d_1^3}{T_1}=\dfrac{P_2d_2^3}{T_2}\\\Rightarrow d_2=(\dfrac{P_1d_1^3T_2}{P_2T_1})^{\dfrac{1}{3}}\\\Rightarrow d_2=(\dfrac{493725\times 0.015^3\times (20+273.15)}{101325\times (10+273.15)})^{\dfrac{1}{3}}\\\Rightarrow d_2=0.0257259766982\ m$

The diameter of the bubble is 0.0257259766982 m

8 0

3 years ago