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True [87]
3 years ago
7

at midnight the temperature in a city was 5 degrees celsius. The temperature was dropping at a steady rate of 2 degrees celsius

per hour. write an inequality that represents t the hours past midnight when the temperature was colder then -4 degrees celsius.
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

( 5 - 2t ) < - 4

Step-by-step explanation:

The midnight temperature is 5 °C and the temperature is decreasing at the rate of 2°C per hour.

If t is the hours past midnight then after t hours the temperature will be ( 5 - 2t ).

Now, if this temperature is colder than - 4° C, then the inequality can be written as   ( 5 - 2t ) < - 4 (Answer)

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Find two consecutive even integers such that the sum of the smaller and 3 times the larger is 330
tensa zangetsu [6.8K]

Answer:

The 2 numbers = 81 and 83

Step-by-step explanation:

As, one number = x

The other, because it's an even number and consecutive = x + 2

So the larger numbef here is x + 2

And they are saying 3 times x + 2 plus x = 330

So let's solve!

3 times x + 2 = 3(x+2) = 3x + 6

So we will add it to x = (3x + 6) +(x) = 4x + 6

So they are saying the sum of them will be 330

So, 4x + 6 = 330

4x = 330 - 6

4x = 324

x = 324/4

x = 81

So x is the first number = 81

And the second is x + 2 = 81 + 2 = 83

So the 2 numbers are 81, 83

Lets check!

3 times the bigger number = 83 x 3 = 249

We will add it to 81 and we will get 330

So, 249 + 81 = 330

So the answer is right

4 0
3 years ago
The morning temperature was –5 °. By noon the temperature was 4 °. How many degrees had the temperature risen? *
valentinak56 [21]

Answer:

9 degress

Step-by-step explanation:

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Find the sum of the first 8 terms in the sequence?
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We need to find the 8 th term nth term is given as <span><span>an</span>=<span>a1</span>+(n−1)d</span> n=8, d =-4 (common difference) <span><span>a8</span>=<span>a1</span>+(8−1)×d</span> <span><span>a8</span>=1+7×(−4<span>)</span></span>
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(15, -8) :)
From C to midpoint you do (+10, -7), so you have to do that again to get to D
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