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Sophie [7]
3 years ago
9

There is a balance of heat coming into and going out of earth. This is known as the?

Physics
2 answers:
valkas [14]3 years ago
3 0
Earths energy budget
kobusy [5.1K]3 years ago
3 0

Answer:

Earth's energy budget states  balance between the energy that the Earth collects from Sun and energy that Earth radiates back into earth orbit after distribution through out the components of Earth's climate system, thereby powering the so-called heat engine of Earth.

Explanation:

Earth's energy budget states  balance between the energy that the Earth collects from Sun and energy that Earth radiates back into earth orbit after distribution through out the components of Earth's climate system, thereby powering the so-called heat engine of Earth.

This particular equilibrium condition is called radiative equilibrium. Around 29% of solar energy reaching the top of atmosphere is transmitted back into space by clouds, dust particles and light surfaces on the ground.

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Consider a car that travels between points A and B. The car's average speed can be greater than the magnitude of its average vel
omeli [17]

Answer:

Explanation:

True

Average speed is the ratio of total distance traveled to the total time taken and average velocity is total displacement to the total time.

And we know distance is either equal to or greater than displacement so we can say that for equal time interval magnitude of average velocity can never be greater than average speed.  

7 0
3 years ago
Elements in the same group/familly of the periodic table are similar in what way
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At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

The average acceleration experimented by the car is:

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\bar a = 1500\,\frac{km}{h^{2}}

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

a = 1500\,\frac{km}{h^{2}}

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A student drew the following model:
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