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fiasKO [112]
3 years ago
15

What is the total negative charge, in coulombs, of all the electrons in a small 0.900 g sphere of carbon? one mole of c is 12.0

g , and each atom contains 6 protons and 6 electrons?
Physics
1 answer:
Setler [38]3 years ago
4 0
The first thing you have to do is find the number of mols. That's done in terms of the masses.
mol = mass of sample / molar mass
mol = 0.900 / 12.0
mol = 0.0750 mol Carbon

Next Each mol of carbon contains 6 mol of electrons. 
mol electrons = 6 * mol of carbon 
mol electrons = 6* 0.0750 = 0.450 mol

Next find out how many electrons are in 0.450 mol
1 mol = 6.02 * 10^23 
0.450 mol  = 6.02 * 10^23 * 0.45 = 2.71 * 10^23 electrons

Finally find the charge in coulombs
1 electron has a charge of 1.60 * 10 ^- 19
2.71 * 10^23 electrons have a charge of 1.6*10^-19 * 2.71*10^23
The answer is 43360 Coulombs = 4.34 * 10^4 coulombs. 

I have deliberately not used textbook formulas because each textbook has its own format.

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Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

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g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Veseljchak [2.6K]

Answer:

The speed of q₂ is 4\sqrt{10}\ m/s

Explanation:

Given that,

Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

E_{i}=E_{f}

\dfrac{1}{2}mv_{i}^2+\dfrac{kq_{1}q_{2}}{r_{i}}=\dfrac{kq_{1}q_{2}}{r_{f}}+\dfrac{1}{2}mv_{f}^2

\dfrac{1}{2}m(v_{i}^2-v_{f}^2)=kq_{1}q_{2}(\dfrac{1}{r_{f}}-\dfrac{1}{r_{i}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{f}^2)=9\times10^{9}\times-2\times10^{-6}\times-8\times10^{-6}(\dfrac{1}{(0.4)}-\dfrac{1}{(0.8)})

0.00075(400-v_{f}^2)=0.18&#10;

400-v_{f}^2=\dfrac{0.18}{0.00075}

-v_{f}^2=240-400

v_{f}^2=160

v_{f}=4\sqrt{10}\ m/s

Hence, The speed of q₂ is 4\sqrt{10}\ m/s

7 0
3 years ago
If an object undergoes a change in momentum of 10 kg m/s in 3 s ,then the force acting on it is
Paha777 [63]

Answer:

Force = 3.333 Newton

Explanation:

Given the following data;

Change in momentum = 10 Kgm/s

Time = 3 seconds

To find the force acting on it;

In Physics, the change in momentum of a physical object is equal to the impulse experienced by the physical object.

Mathematically, it is given by the formula;

Force * time = mass * change in velocity

Impulse = force * time

Substituting into the formula, we have;

10 = force * 3

Force = 10/3

Force = 3.333 Newton

8 0
3 years ago
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