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fiasKO [112]
3 years ago
15

What is the total negative charge, in coulombs, of all the electrons in a small 0.900 g sphere of carbon? one mole of c is 12.0

g , and each atom contains 6 protons and 6 electrons?
Physics
1 answer:
Setler [38]3 years ago
4 0
The first thing you have to do is find the number of mols. That's done in terms of the masses.
mol = mass of sample / molar mass
mol = 0.900 / 12.0
mol = 0.0750 mol Carbon

Next Each mol of carbon contains 6 mol of electrons. 
mol electrons = 6 * mol of carbon 
mol electrons = 6* 0.0750 = 0.450 mol

Next find out how many electrons are in 0.450 mol
1 mol = 6.02 * 10^23 
0.450 mol  = 6.02 * 10^23 * 0.45 = 2.71 * 10^23 electrons

Finally find the charge in coulombs
1 electron has a charge of 1.60 * 10 ^- 19
2.71 * 10^23 electrons have a charge of 1.6*10^-19 * 2.71*10^23
The answer is 43360 Coulombs = 4.34 * 10^4 coulombs. 

I have deliberately not used textbook formulas because each textbook has its own format.

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Hello!

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4 0
3 years ago
What is one property of iodine
mamaluj [8]

Answer: I2

Explanation:

6 0
3 years ago
approximation to the average velocity in that time interval, what should be the sequence of calculations?Update the (vector) pos
Klio2033 [76]

Answer:

The steps are outlined in the explanation below.

Explanation:

The average velocity is derived midpoint from the initial to the final velocity. Here is the proof:

Find the total displacement:

let the displacement be given by the letter s

Then since the average velocity is defined as:  v_{av}  = \frac{x - x_{0} }{t - t_{0} }

where t = final time

           t₀ = initial time

           v = final speed

           v₀ = initial time

where x denotes the position, then

v_{ave} = \frac{v+v_{0} }{2}

where v = \frac{dx}{dt} and dx = change in distance with respect to time.

6 0
3 years ago
A circular coil of radius r = 5 cm and resistance R = 0.2 is placed in a uniform magnetic field perpendicular to the plane of th
Yuri [45]

Answer:

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

E=-\frac{d}{dt}(BACOS\alpha )\\

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using \pi r^{2} \\ where r is the radius of 5cm or 0.05m

A=\pi *(0.05)^{2}\\ A=0.00785m^{2}\\

since we no that the angle is at 0^{0}

we determine the magnitude of the magnetic filed

B=0.5e^{-t} \\t=2s

E=-(0.5e^{-2} * 0.00785)

E=-0.000532v\\

the Magnitude of the voltage is 0.000532V

Next we determine the current using ohm's law

V=IR\\R=0.2\\I=\frac{0.000532}{0.2} \\I=0.0026A

I=2.6mA

6 0
4 years ago
Lewiston and Vernonville are 208 miles apart. A car leaves Lewiston traveling towards​ Vernonville, and another car leaves Verno
iragen [17]

Answer:

Average speed of the car A = 70 miles per hour

Average speed of the car B = 60 miles per hour

Explanation:

Average speed of the car A is v_{A} =\frac{x_{A} }{t_{A} } (Equation A) and Average speed of the car B is v_{B} =\frac{x_{B} }{t_{B} } (Equation B), where x_{A} and x_{B} are the distances and t_{A} and t_{B} are the times at which are travelling the cars A and B respectively.

We have to convert the time to the correct units:

1 hour and 36 minutes = 96 minutes

96 minutes . \frac{1 hour}{60 minutes} = 1.6 h

From the diagram (Please see the attachment), we can see that at the time they meet, we have:

v_{A} = \frac{208-x}{1.6h} + 10\frac{miles}{h} (Equation C)

v_{B} = \frac{208-x}{1.6h} (Equation D)

From Equation A and C, we have:

\frac{208-x}{1.6}+10 = \frac{x}{1.6}

208-x+16 = x

208 + 16 = 2x

x = \frac{224}{2}

x = 112 miles

Replacing x in Equation A:

v_{A}  = \frac{112miles}{1.6h}

v_{A} = 70 miles per hour

Replacing x in Equation B:

v_{B}  = \frac{208miles-112miles}{1.6h}

v_{B}  = \frac{96miles}{1.6h}

v_{B}  = 60 miles per hour

3 0
3 years ago
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