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mote1985 [20]
3 years ago
15

Arman is working on his homework four statements from his homework or below use yes or no to indicate whether each statement is

true
Chemistry
1 answer:
Whitepunk [10]3 years ago
5 0
Where are the statements
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Methyl bromide (CH3Br) a. is extremely flammable b. is of greater concern from its oral toxicity than from its inhalation toxici
Mekhanik [1.2K]

Answer:

I believe it is C.

Explanation:

Hope my answer has helped you and if not i'm sorry.

4 0
3 years ago
Which of the following would cause a decrease in the volume of a sealed balloon filled with air? (2 points) addition of another
monitta
A decrease in temperature will cause a decrease in the volume of a sealed balloon filled with air. Temperature and pressure usually act together.This is because, reducing the temperature of a volume of gas will reduce the kinetic energy of the atoms of the gas, leading to a slower movement of the atoms and thus reducing the number of time the particles of the gas collide will the wall of the container; this means that the pressure has been reduced. This will reduce the volume of the gas. The reverse is also true.  
7 0
3 years ago
Which accurately labels the lysosome?<br><br> W<br> X<br> Y<br> Z
xeze [42]
I am not sure about this but I think it’s y
7 0
3 years ago
Read 2 more answers
2HgO—&gt;2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?
jok3333 [9.3K]

Answer:

Theoretical yield = 3.52 g

Percent yield =65.34%

Explanation:

Given data:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ =  2.30 g

Solution:

Chemical equation:

2HgO  →   2Hg + O₂

Number of moles of HgO = mass/ molar mass

Number of moles of HgO = 46.8 g / 216.6 g/mol

Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

                         HgO             :             O₂

                             2               :               1

                            0.22           :          1/2×0.22 = 0.11 mol

Theoretical yield:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  0.11 mol × 32 g/mol

Mass of oxygen = 3.52 g

Percent yield :

Percent yield = actual yield / theoretical yield × 100

Percent yield = 2.30 g/ 3.52 g × 100

Percent yield =65.34%

5 0
3 years ago
Which statement is true regarding methane and ammonia?
sukhopar [10]
The options for given question are as follow,

1) Methane molecules show hydrogen bonding. 
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
            Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
                   Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
6 0
3 years ago
Read 2 more answers
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