Answer:
45
Step-by-step explanation:
Every 15 minutes, 30 kilometers are passed by.
15/60 = 1/4 hour
30/120 = 1/4 speed
Answer: 20 km
Step-by-step explanation: Let's assume a trajectory of Ships A (which is moving at 6 km/h) and B (which is moving at 4 km/h)
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A 10 km B
And let's assume that who is going to the right is the positive.
Space (S) = S₀ + vt
For A, its space is SA = 0 + 6t
For B, its space is SB = 10 - 4t
They meet at SA = SB;
6t = 10 - 4t
6t + 4t = 10
10t = 10
t = 1h
If the bird is at 20 km/h and it will fly for 1h, it will travel 20 km
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
Answer:
(1,-5)
Step-by-step explanation:
recall that for any function g(x), we can equate the function to y,
i.e y = g(x), where any point (x,y) that satisfies the equation is considered a point on the graph
in our case we are given, that g(1) = -5, rearranging:
-5 = g(1)
if we compare this with the the equation above y = g(x),
we can see clearly that y = -5 and x = 1.
and from our reasoning given in the paragraph above, we can say that (1,-5) is a point on the graph.
So in this case expand the brackets where everything outside the brackets are multiplied into the brackets if that makes sense. Therefore 5 times 3m plus 5 time 2.
(5×3m)+(5×2)
=15m+10
do not add them together since they are not like terms
Do the same for the next question
which I think is already done for you since there is no expanding or adding to do.
Hope I am right if not sorry.