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user100 [1]
4 years ago
15

_______ can be used to prevent busy waiting when implementing a semaphore.

Computers and Technology
1 answer:
gregori [183]4 years ago
8 0

Answer:

b) waiting queues

Explanation:

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Regularly tuning up a computer can assist with keeping it running at peak speed.
Lady_Fox [76]
The answer to your question, is true
hope this helps :D
3 0
3 years ago
The communication channel used in IMC must rev: 12_06_2018_QC_ CDR-223 Multiple Choice match the traditional channel used in tha
Setler [38]

Answer:

connect the sender with the desired recipients.

Explanation:

Integrated Marketing Communication (IMC) is a process through which organizations create seamless branding and coordination of their marketing and communication objectives with its business goals and target audience or consumers. The communication tools used in IMC are both digital and traditional media such as billboards, search engine optimization, magazines, television, blog, radio, webinars etc.

The communication channel used in IMC must connect the sender with the desired recipients.

The receiver is any individual who is able to read, hear or see and process the message being sent or communicated in the IMC communication process. Any interference the IMC communication process is known as noise.

An organization can analyze and measure the effectiveness of the IMC communication process by considering market share, sales, and customer loyalty.

5 0
3 years ago
Determine the number of bytes necessary to store an uncompressed RGB color image of size 640 × 480 pixels using 8, 10, 12 and 14
dexar [7]

Answer:

For 8 bits / Color Channel: 921, 600 bytes.

For 10 bits / Color Channel: 1,152,000 bytes.

For 12 bits / Color Channel: 1,382,400 bytes.

For 14 bits / Color Channel : 1,612, 800 bytes.

Explanation:

Un uncompressed RGB color image of 640 pixels wide by 480 pixels height (VGA resolution) uses 3 samples of x bits fin order to represent the quantity of each primary color (red, green and blue) in a given pixel of the image.

So, if we use 8 bits/ sample, we can calculate the bytes needed to store a complete image as follows:

640*480*3*8 bits = 7, 372,800 bits. (1)

As, by definition, 1 byte= 8 bits, we have:

Nº of bytes = 7,372,800 / 8 = 921,600 bytes. (2)

In order to get the bytes needed to store the same image, using 10, 12 and 14 bits/ sample, all we need is replacing 8 by 10, 12 and 14 in (1), and then dividing by 8 as in (2).

Proceeding in this way we obtain:

640*480*3*10 = 9,216,000 bits ⇒    1,152,000 bytes.

640*480*3*12 = 11,059,200 bits ⇒   1,382,400 bytes.

640*480*3*14=   12,902,400 bits ⇒  1,612,800 bytes.

8 0
4 years ago
A user of the system
iragen [17]

Answer:

ummm what system. have to be more specific ^^

Explanation:

8 0
3 years ago
Did every packet arrive in the correct order? Describe what went wrong and whether your partner was able
snow_lady [41]

Answer:

to answer this question I am going to need a little bit more info

Explanation:

6 0
3 years ago
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