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kap26 [50]
3 years ago
14

--Please help!--

Physics
1 answer:
enot [183]3 years ago
6 0

Answer:

C) Amplitude.

Explanation:

By definition, the amplitude of wave is defined as the distance from the rest position to the highest or lowest point of the wave.

The highest and lowest points of the wave are called crests and troughs respectively; Therefore, the amplitude of the waves is also said to be the height of the wave from its rest position to its crest—and also the height of the from the rest position it its trough.

This means Choice C (amplitude) is the correct term used to describe the height of a wave from its rest position to its crest.

<em>P.S: Choice A, the crest height, can also be the correct term, but the term ''amplitude'' is often used and is more technical. </em>

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4 0
3 years ago
A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0
2 years ago
What are the potential out comes of force
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Answer:

F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.

Explanation:

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