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devlian [24]
3 years ago
7

Many species cool themselves by sweating, because as the sweat evaporates, heat is transferred to the surroundings. A human exer

cising strenuously has an evaporative heat loss rate of about 650 W. If a person exercises strenuously for 29.1 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is 2430 J/g at normal skin temperature.
Physics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

70713

Explanation:

Because you need to multiply the amount of water lost (2430) by the time (29.1) which will equal 70713J/g needed to counter the loss.

Hope this helps:)

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Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

     = (9×10^9)×(q)/(24.0)

     = 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

                       R^2 = 9×r^2

E2 = k×q/(9×r^2)

     = k×q/(9×375000000q)

     = k/(9×375000000)

     = (9×10^9)/(9×375000000)

     = 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

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