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disa [49]
3 years ago
12

A fast pitch softball player does a "windmill" pitch moving her hand through a vertical circular arc to pitch a ball at 70mph. T

he 0.19 kg ball is 55 cm from the pivot point at her shoulder.
Just before the ball leaves her hand, what is its centripetal acceleration?
Physics
1 answer:
uysha [10]3 years ago
8 0

Answer:

Explanation:

The hand throwing ball moves on a circular path having radius r = .55 m

mass of ball m = .19 kg

velocity v = 70 mph

= 70 x 1600 / 60 x 60

= 31.11 m /s

centripetal force

= mv² / r

= .19 x 31.11² / .55

= 334.34 N

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