Answer:
The solution and the explanation are in the Explanation section.
Explanation:
According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:
TA = W * (a * cosθ)
The torque due to effort at C point is:
TC = E * (b * cosθ)
The net torque is equal to 0, we have:
Tnet = 0
W * (a * cosθ) - E * (b * cosθ) = 0
From the figure, you can observe that a/b < 1, thus E < W
Answer:
Total momentum, p = 21.24 kg-m/s
Explanation:
Given that,
Mass of first piece,
Mass of the second piece,
Speed of the first piece, (along x axis)
Speed of the second piece, (along y axis)
To find,
The total momentum of the two pieces.
Solve,
The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.
The net momentum is given by :
p = 21.24 kg-m/s
Therefore, the total momentum of the two pieces is 21.24 kg-m/s.