Answer:
Approximately 
.
Assumption: air resistance on the rocket is negligible. Take 
.
Explanation:
By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.
.
Note that in this case, the uppercase letter 
in the units stands for "mega-", which is the same as 
times the unit that follows. For example, 
, while 
.
Convert the mass of the rocket and the thrust of its engines to SI standard units:
- The standard unit for mass is kilograms:
. - The standard for forces (including thrust) is Newtons:
.
At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:
- Thrust (which is supposed to go upwards), and
- Weight (downwards due to gravity.)
The thrust on the rocket is already known to be 
. Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately 
. Hence, the weight on the rocket would be approximately 
.
The magnitude of the net force on the rocket would be
.
Apply the formula to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)
.
While the total energy<span> of a system is always conserved, the </span>kinetic energy<span> carried by the moving objects is not always conserved. In an inelastic collision, </span>energy<span> is </span>lost<span> to the environment, transferred into other forms such as heat.
Hope this helps.</span>
0.975 is correct, to get the answer you divide the length value by 10.
I only know the formula which is ω = 2πf
