Question

During a trial run, race car A starts from rest and accelerates uniformly along a straight level track for a particular interval of time. Race car B also starts from rest and accelerates at the same rate, but for twice the time. At the end of their respective acceleration periods, which of the following statements is true? Car A has traveled a greater distance. Car B has traveled twice as far as A. Car B has traveled four times as far as car A. Both cars have traveled the same distance

Answer 1

Answer: car B has travelled 4times as far as Car A

d=vi*t+1/2at^2

No initial velocity so equation becomes;

d=1/2at^2 and the acceleration is the same between both only time is different;

Car A d=1/2a(1)^2

Car B d=1/2a(2)^2

Car A d= 1^2=1

Car B d= 2^2=4

Car B d=4*Car A

So car B has travelled 4 times as far as car A