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valentinak56 [21]
3 years ago
11

At 25.0∘C, the molar solubility of barium chromate in water is 1.10×10−5 M . Calculate the solubility in grams per liter.

Chemistry
1 answer:
Lunna [17]3 years ago
7 0
Hey there!

Molar mass :
<span>
 ‎BaCrO</span>4 =  ‎253.319 g/mol

(g/L) = molar solubility * molar mass

(g/L) =  ( 1.10 x 10⁻⁵ ) * 253.319

=> 2.79x10⁻³ g/L
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