Oxygen is the correct answer hope this helps
pKa is a value which is related to the acid dissociation constant Ka
pKa = -log Ka
i.e. Ka = 10^-pKa
The deprotonation reaction of acetylene is:
HC≡CH ↔ HC≡C⁻ + H⁺
pKa (HC≡CH) = 25
Solvents with pKa greater than 25 will deprotonate acetylene.
Ans: CH2=CH⁻ pka = 44 and CH3NH⁻ pka = 40
Answer: polar protic solvents solvate the nucleophile necessary for attack on the substrate in SN2 substitution.
Explanation:
Aprotic solvents are solvents that lack protons such as dimethyl sulphoxide (DMSO). DMSO has no exposed positive end. The positive end is buried inside the molecular structure. As a result of this, the nucleophile is not solvated. If the nucleophile is solvated, the rate of SN2 reaction will reduce drastically because the nucleophile becomes unavailable to attack the substrate. This solvation normally occur in polar protic solvents such as water because of the exposed positive end of the molecule which interacts with the nucleophile thereby reducing the rate of SN2 reaction.
Answer:
Proteins, fats, carbohydrates, vitamins link, minerals link, and water are nutrients. Your digestive system breaks nutrients into parts small enough for your body to absorb and use for energy, growth, and cell repair.
Explanation:
The Half-Life of the radioactive sample is 8.1 hours.
<h3>What is half life of a radioactive element?</h3>
The half-life of a radioactive substance is the time taken for half the amount of atoms in the given substance to decay.
12.5 grams remains out of 100 grams of the sample.
This is 1/8 of the original samples.
1/8 of the original sample reperesent three half-lives undergone.
Half-Life of the radioactive sample = 24.3/3 = 8.1 hours
Therefore, the Half-Life of the radioactive sample is 8.1 hours.
Learn more about Half-Life at: brainly.com/question/25750315
#SPJ1