The Ksp of Mg(OH)2 in water is 1.8 x 10-<span>11. This means that in pure water, Mg(OH)2 has a solubility of:
</span>∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
<span>which is equal to
</span>1.65 x 10-4<span> mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL
If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
</span>1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL
I think it’s heat transfer but can’t guarantee
Answer:
Exactly the same approach can be used for determination of bromides. Other halides and pseudo halides, like I- and SCN-, behave very similarly in the solution, but their precipitate tends to adsorb chromate anions making end point detection difficult.
Hope it helps!
The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.
Molarity has been defined as the moles of substance in a liter of solution. Molarity has been expressed as:

<h3>Computation for moles of Barium nitrate</h3>
The given barium nitrate solution has the volume of 0.25 L.
The molarity of the solution has been 2 M.
Substituting the values for the moles of Barium nitrate

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.
Learn more about molarity, here:
brainly.com/question/12127540