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olasank [31]
3 years ago
15

Which ion formation takes more energy: K+ or Li+?

Chemistry
1 answer:
Dima020 [189]3 years ago
3 0

Answer:

Li⁺

Explanation:

In ion formation, the ionization energy plays a very important role. To form an ion, an atom will lose or gain an electron to become charged.

The higher the ionization energy of an atom, the more the energy required to remove an electron from it to form an ion.

  • Ionization energy is the energy required to remove an electron from an atom.
  • It is the readiness of an atom to lose an electron. The lower the value, the easier it is for an atom to lose an electron and vice versa.

Generally, down the group, ionization energy decreases. Since both potassium and lithium are in group 1, Li will have a higher ionization energy. It will take more energy to form Li⁺ compared to K⁺.

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For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min
abruzzese [7]

Answer:

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

V = V_{max}\times \frac{[S]}{ (Km + [S])}

V_{max }=k_{cat}\times E_o

Where  :

V_{max} = max rate velocity

[S] = substrate concentration

K_m = Michaelis-Menten constant

V = reaction rate

k_{cat} = catalytic rate constant

E_o = initial enzyme concentration

We have :

K_m=10.0mM

E_o=10.0\mu M=10.0\times 0.001 mM

V_{max}=0.172 mM/min

V_{max} is the rate is obtained when all enzyme is bonded to the substrate. k_{cat} is termed as the turnover number.

k_{cat}=\frac{V_{max}}{E_o}=\frac{0.172 mM}{10.0\times 0.001 mM}

=17.2 minutes

17.2 minutes is the value of the turnover number.

3 0
3 years ago
Calculate how many grams of o2(g) can be produced from heating 87.4 grams of kclo3(s).
Rufina [12.5K]
<span>34.2 grams Lookup the atomic weights of the involved elements Atomic weight potassium = 39.0983 Atomic weight Chlorine = 35.453 Atomic weight Oxygen = 15.999 Molar mass KClO3 = 39.0983 + 35.453 + 3 * 15.999 = 122.5483 g/mol Moles KClO3 = 87.4 g / 122.5483 g/mol = 0.713188188 mol The balanced equation for heating KClO3 is 2 KClO3 = 2 KCl + 3 O2 So 2 moles of KClO3 will break down into 3 moles of oxygen molecules. 0.713188188 mol / 2 * 3 = 1.069782282 mols So we're going to get 1.069782282 moles of oxygen molecules. Since each molecule has 2 atoms, the mass will be 1.069782282 * 2 * 15.999 = 34.23089345 grams Rounding the results to 3 significant figures gives 34.2 grams</span>
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3 years ago
A heavy textbook and a QOD journal sit on the edge of your desk. Which has more gravitational potential energy?
fenix001 [56]
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4 0
3 years ago
An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for
8090 [49]

Answer: The freezing point and boiling point of the solution are -6.6^0C and 101.8^0C respectively.

Explanation:

Depression in freezing point:

T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = freezing point of solution = ?

T^o_f = freezing point of water = 0^0C

k_f = freezing point constant of water = 1.86^0C/m

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

w_2 = mass of solute (ethylene glycol) = 21.4 g

w_1= mass of solvent (water) = density\times volume=1.00g/ml\times 97.6ml=97.6g

M_2 = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

T_f=-6.6^0C

Therefore,the freezing point of the solution is -6.6^0C

Elevation in boiling point :

T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of water = 100^0C

k_b = boiling point constant of water = 0.52^0C/m

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

w_2 = mass of solute (ethylene glycol) = 21.4 g

w_1= mass of solvent (water) = density\times volume=1.00g/ml\times 97.6ml=97.6g

M_2 = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}

T_b=101.8^0C

Thus the boiling point of the solution is 101.8^0C

4 0
3 years ago
The dots in these cylinders represent the shape and
Elden [556K]

Answer:

A I think

Explanation:

Because plasma have ions and B is neutralized with two ions

8 0
3 years ago
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