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Aleks04 [339]
3 years ago
11

a class of 25 students shares a class set of 100 markers.on a day with 5 students absent,which statement is true ​

Mathematics
1 answer:
solong [7]3 years ago
4 0

Answer:

Every student would have five markers.

Step-by-step explanation:

There would be 20 students, and 100 markers which is 20/100. You would reduce that fraction to 1/5. Therefore, every student would have 5 markers.

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Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (13, 84) lies
erma4kov [3.2K]

Answer:

If P = (x,y) then formulas for each trigonometric functions are:

sin x = y/r

cos x = x/r

tan x = y/x

cot x = x/y

sec x = r/x

cosec x = r/y

where r = √(x²+y²).

First find r:

r = √(13²+84²)=√(169+7056)=√7225=85.

Then just substitute:

sin x = 84/85

cos x = 13/85

tan x = 84/13

cot x = 13/84

sec x = 85/13

cosec x = 85/84

3 0
3 years ago
Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?
spayn [35]

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

\frac{d}{dx}\cdot f(x)

Now the sum of the 2 functions is shown below

y=f(x)+g(x)

Diffrentiating both sides with respect to 'x' we get

\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

\frac{dy}{dx}

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

h=f(x)\cdot g(x)

Diffrentiating both sides with respect to 'x' we get

h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

8 0
3 years ago
Because of their small size, the sea lion pups are more vulnerable to changes in their environment and are less able to adapt to
Wittaler [7]
? Whats the question? This is a statement??
7 0
3 years ago
Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and
pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0
3 years ago
Read 2 more answers
If on the unit circle C , the distance from P (1, 0) to the point T ( 5/13, 12/13 ) is x , determine the coordinates of the poin
Lorico [155]

Answer:

T' (\frac{5}{13},- \frac{12}{13})

Step-by-step explanation:

See the diagram attached.

This is a unit circle having a radius (r) = 1 unit.

So, the length of the circumference of the circle will be 2πr = 2π units.

Now, the point on the circle at a distance of x along the arc from P is T(\frac{5}{13},\frac{12}{13}).

Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' (\frac{5}{13},- \frac{12}{13}), where, T' is the image of point T, when reflected over the x-axis. (Answer)

6 0
3 years ago
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