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3 years ago

15

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la

unch points.
*Force

2 answers:

Nimfa-mama [501]3 years ago

6 0

Force is the interaction that changes the motion of an object. If we want to make a jump, our legs have to exert a force to the ground (or launch points), so that we can gain an equal and opposite force that changes our motion from being static on the ground to moving forward.

Hatshy [7]3 years ago

5 0

Force applied to building propels the object forward.

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A radioactive substance decays according to the formula w = 20e¡kt grams where t is the time in hours. a find k given that after

blagie [28]

W=20 e(-kt)
A. Rearranging gives k= -(ln(w/20)/t
Substituting w= 10 and solving gives k=0.014
B. Using W=20e(-kt). After 0 hours, W=20. After 24 hours, W=14.29g. After 1 week (24x7=168h) W=1.9g
C. Rearranging gives t=-(ln(10/20)/k. Substituting w=1 and solving gives t=214 hours.
D. Differentiating gives dW/ dt = -20ke(-kt). Solving for t=100 gives dW/dt = 0.07g/h. Solving for t=1000 gives 0.0000002g/h
E. dW/dt = -20ke(-kt). But W=20e(-kt) so dW/dt = -kW

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3 years ago

1. The property of a material to absorb liquid like water is called

frez [133]

Answer:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

Explanation:

A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption.

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2 years ago

A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio

MAVERICK [17]

If friction is acting along the plane upwards

then in this case we will have

For equilibrium of 100 kg box on inclined plane we have

$mgsin\theta = F_f + T$

also for other side of hanging mass we have

$T = Mg = 50(9.8) = 490 N$

now we have

$100(9.8)sin\theta = 100 + 490$

$980sin\theta = 590$

$sin\theta = 0.602$

$\theta = 37 degree$

In other case we can assume that friction will act along the plane downwards

so now in that case we will have

$mgsin\theta + F_f = T$

also we have

$T = Mg = 50(9.8) N$

now we have

$100(9.8)sin\theta + 100 = 50(9.8)$

$980sin\theta + 100 = 490$

$980 sin\theta = 490 - 100$

$sin\theta = 0.397$

$\theta = 23.45 degree$

<em>So the range of angle will be 23.45 degree to 37 degree</em>

6 0

3 years ago

Does anyone know question 6?

vfiekz [6]

Answer:

Yes, the fuse will blow.

Explanation:

We'll begin by converting 50000mA to amperes (A) .this is illustrated below:

1000mA = 1A

Therefore, 50000mA = 50000/1000 = 50A.

From the question given above, the plug can only accommodate 5A. Now if 50000mA i.e 50A is passed through the plug, the plug will blow because the 50A is higher than what the plug can accommodate.

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3 years ago

An electron of mass 9.11×10-31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to t

SOVA2 [1]

Answer:

(A) Acceleration will be $240.3846\times 10^{12}m/sec^2$

(b) Time taken will be $1.4\times 10^{-8}sec$

(c) Force will be $2189.9\times 10^{-19}N$

Explanation:

We have given that electron starts from rest so initial velocity u = 0 m/sec

Final velocity $v=2.50\times 10^6m/sec$

Mass of electron $m=9.11\times 10^{-31}kg$

Distance traveled by electron $s=1.30cm =0.013m$

From third equation of motion we know that $v^2=u^2+2as$

(a) So $(2.5\times 10^6)^2=0^2+2\times a\times 0.013$

$a=240.3846\times 10^{12}m/sec^2$

(b) From first equation of motion we know that v = u+at

So $2.50\times 10^6=0+240.3846\times 10^{12}t$

$t=0.014\times 10^{-6}=1.4\times 10^{-8}sec$

(c) From newton's law we know that force

$F=ma=9.11\times 10^{-31}\times 240.3846\times 10^{12}=2189.9\times 10^{-19}N$

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3 years ago