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Airida [17]
3 years ago
15

ME PUEDEN DECIR EJERCICIOS DE RESISTENCIA AÉROBICOS Y ANAERÓBICOS POR FAAA :C ES URGENTE *Me lo explican bien pliis para saber k

omo hacerlo :)
Physics
1 answer:
Anvisha [2.4K]3 years ago
6 0

Explanation:

sksksksmsmamamamamamamamama

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What are the names of the four hemispheres of the earth
xenn [34]

Explanation:

Northern, Southern, Eastern, and Western.

6 0
3 years ago
Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
Fofino [41]

Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.

ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

3D₁² = (D₁²/4) × v₂

(D₁²/4) × v₂ = 3D₁²

v₂ = 4×3 = 12 m/s

8 0
3 years ago
9.Water flows'along a horizontal pipe of cross sectional area 48cm2 which has a constriction of
Kamila [148]

Answer:

v₁ = 9 m/s

Explanation:

Here, we can use the continuity equation, as follows:

A_1v_1 = A_2v_2

where,

A₁ = Cross-sectional area of the wider section = 48 cm²

A₂ = Cross-sectional area of the constriction = 12 cm²

v₁ = speed of flow in wider section = ?

v₂ = speed flow in constriction = 36 m/s

Therefore,

(48\ cm^2)v_1 = (12\ cm^2)(36\ m/s)\\\\v_1 = \frac{(12\ cm^2)(36\ m/s)}{(48\ cm^2)} \\\\

<u>v₁ = 9 m/s</u>

3 0
3 years ago
an open rectangular tank 1.0 meter wide and 2.0 meter long contains gasoline to a depth of 1.5 meters. if the height of the tank
Alekssandra [29.7K]

The maximum horizontal acceleration is solved to be 4.91 m/s^2

<u />

<h3>What is acceleration?</h3>

This is a term in physics that refers to change in velocity with time.  Acceleration can be positive or negative or zero,

<u />

<u>Given data</u>

open rectangular tank

width = 1.0 m

length = 2.0 m

gasoline depth level = 1.5 m

height of the tank = 2.0 m

<h3>How to solve for maximum horizontal acceleration</h3>

lets represent the volume with x, y, and z such that z corresponds to height, y corresponds to wide or width, and x corresponds to length.  

dz / dy = - ay / ( g + az )

where

ay = acceleration in the y direction

az = acceleration in the z direction which is equal to zero

g = acceleration due to gravity

plugging in az = 0

dz / dy = - ay / ( g )

ay = - ( dz / dy ) * g

to prevent spilling

dz / dy = -  ( 1.5 - 1 ) / 1

dz / dy = -  0.5

ay = - ( - 0.5 ) * 9.81

ay = 4.91 meters per second square

Hence the maximum horizontal acceleration is solved to be 4.91 m/s^2

Read more on acceleration here: brainly.com/question/605631

#SPJ1

7 0
2 years ago
If Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?​
Nastasia [14]

Answer:

10g

Explanation:

As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".

Though melting of tin isn't a chemical change, the same logic is applied here...

Hence,

The mass of tin will be 10 g itself...

7 0
4 years ago
Read 2 more answers
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