A ______________________ is the distance from one compression to the next compression in a longitudinal wave.

A compound is 53.31% c, 11.18% h, and 35.51% o by mass. what is its empirical formula?

Alexus [3.1K]

<span>Your final answer would be C4H10O2, which equals 90amu</span>

3 0

3 years ago

What is the mass of a 1.68-l sample of a liquid that has a density of 0.921g/ml?

Gwar [14]

Hey there!

Volume in mL :

1.68 L * 1000 => 1680 mL

Density = 0.921 g/mL

Therefore:

Mass = density * Volume

Mass = 0.921 * 1680

Mass = 1547.28 g

7 0

3 years ago

In order to improve the condition of your muscular system, you could participate in aerobic activity at least __________. A. 3 m

zlopas [31]

I think it would be C

5 0

3 years ago

Read 2 more answers

What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l

Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law: $PV=nRT$ where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units: $R=0.0821\frac{L\cdot atm}{mol\cdot K}$

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means $T=273.15K$ and $P=1atm$

Lastly, we must calculate the number of moles of $O_2(g)$ there are. Given 0.80g of $O_2(g)$ , we will need to convert with the molar mass of $O_2(g)$ . Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2: $32g\text{ }O_2=1mol\text{ }O_2$

Thus, $\frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n$

Isolating V in the Ideal Gas Law:

$PV=nRT$

$V=\frac{nRT}{P}$

...substituting the known values, and simplifying...

$V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}$

$V=0.56L \text{ } O_2$

So, 0.80g of $O_2(g)$ would occupy 0.56L at STP.

5 0

2 years ago

Read 2 more answers

What do methanol (CH2O), ethanoic acid (C2H4O2), and glucose (C3H6O3) all have in common?

tatyana61 [14]

Answer:

d

Explanation:

Carbohydrates are compounds containing carbon, hydrogen, and oxygen. Therefore, a is true.

An empirical formula is the simplest ratio of atoms present in a compound. Therefore, C2H4O2 and C3H6O3, (if you simplified them like you would a fraction) would be CH2O. Therefore b is correct,

They also have the same % composition, with a ratio of 1 carbon : 2 hydrogen : 1 oxygen. Therefore, c is correct.

Since a, b and c are all correct, the answer is d, all of the above are true.

6 0

4 years ago