All categories

3 years ago

Give the Unabbreviated electron configuration for barium

Chemistry

1 answer:

Shalnov [3]3 years ago

8 0

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n = 2 + 8 + 8 + 18 + 18 + 2 = 56

You might be interested in

Calculate the mole fraction of each component in a solution with 6.87 g of sodium chloride (NaCl) dissolved in 65.2 g of water.

zheka24 [161]

Answer:

mole fraction of NaCl = 0.03145.

mole fraction of water = 0.9686.

Explanation:

Mole fraction is an expression of the concentration of a solution or mixture.

It is equal to the moles of one component divided by the total moles in the solution or mixture.

The summation of mole fraction of all mixture components = 1.

mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).

no. of moles of NaCl = mass/molar mass = (6.87 g)/(58.44 g/mol) = 0.1176 mol.

no. of moles of water = mass/molar mass = (65.2 g)/(18.0 g/mol) = 3.622 mol.

∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.

∵ mole fraction of NaCl + mole fraction of water = 1.0.

∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.

7 0

3 years ago

Can Magnesium hydroxide be used as the base for this titration? Why or why not? 5. Describe the procedure that you will follow t

kvasek [131]

Explanation:

Yes

2KHP + Mg(OH)2 = 2KOH + Mg(HP)2

KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

= (12*8) + (5*1) + 39 + (16*4)

= 204 g/mol

Number of moles = mass/molar mass

= 20.4/204

= 0.1 mol.

• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O

1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

= 0.00125 mol.

Molarity = number of moles/volume

= 0.00125/0.01

= 0.125 M of Ba(OH)2.

4 0

3 years ago

If 450.0 mL of a 0.500 M solution is mixed with 200.0 mL of water, what is the molarity of the new

Oksana_A [137]

Answer:

Answer: A) .346 M

Explanation:

Given:

- 450 mL

- .5 M soln

-200 mL water

1) Convert mL to L

450 mL = .45 L

200 mL = .2 L

2) Find mols in solution

.5 M = x/.45 L

x = .225 mol

3) Find total volume of solution

.45 L + .2 L =.65 L

4) Find new molarity

molarity (M) = mols solute/ L solution

y = .225 mol (from step 2)/ .65 L (from step 3)

y = .346 M

Answer: A) .346 M

7 0

3 years ago

What kind of bond holds together atoms within a molecule?

sesenic [268]

I think it would be these three answers ionic , covalent , and polar covalent

7 0

3 years ago

Read 2 more answers

___________ reactions form predominately or exclusively one enantiomer. ____________ is the addition of a single oxygen atom to

ArbitrLikvidat [17]

1) Stereo-selective (or enantioselective) reactions form predominately or exclusively one enantiomer.

2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.

3) Hydrogenation (or reduction) of an alkene forms an alkane by addition of H₂.

4) Dihydroxylation is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.

5) oxidative cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.

6) Regioselective reactions form predominately or exclusively one constitutional isomer.

7) Syn dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.

7 0

3 years ago