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3 years ago

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An object is moving north at a constant speed. A force of 5 N begins to push the object east at the same moment that a force of

5 N begins to push it west. What will happen to the object?

2 answers:

Svetllana [295]3 years ago

7 0

Since both the forces are equal in magnitude (5N) and opposite in direction (one is toward the east and the other, the west), they'll cancel out each other, and the object will continue moving north

Hope this answered your question

earnstyle [38]3 years ago

4 0

Answer:

The object will continue to move in the north direction.

Explanation:

Given that,

Force = 5 N

An object is moving in the north direction at a constant speed.

A force of 5 N starts to push the object in the east direction at the same magnitude that a force of 5 N starts to push it west.

Consequently, These forces will be cancelled because they are same and opposite.

Therefore, Both the forces will have no effect on the object.

Hence, The object will continue to move in north direction.

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Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at

netineya [11]

Answer:

Δu=1300kJ/kg

Explanation:

Energy at the initial state

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Is saturated vapor at initial pressure we have

$p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)$

Process 2-3 is a constant volume process

$p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)$

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

$=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg$

Δu=1300kJ/kg

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3 years ago

A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t

borishaifa [10]

Answer:

Angular acceleration will be $18.84rad/sec^2$

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity $\omega _i=0rev/sec$

And final angular velocity $\omega _f=24rev/sec$

Time is given as t = 8 sec

From equation of motion

We know that $\omega _f=\omega _i+\alpha t$

$24=0+\alpha \times 8$

$\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2$

So angular acceleration will be $18.84rad/sec^2$

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4 years ago

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To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire $(m) = 1.10g = 1.10*10^{-3} kg$

Density $(\rho)= 8.92*10^3kg/m^3$

Resistively of copper $(\gamma) = 1.7*10^{-8}\Omega \cdot m$

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Volume is defined as,

$V= lA \text{ and }\frac{m}{\rho}$

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$lA = 1.233*10^{-7} m^3$ (1)

We know that,

$\frac{l}{A} = \frac{R}{\gamma}$

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$\frac{l}{A} = 2.2941*10^7 m^{-1}$ (2)

Multiplying equation we have

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Explanation:

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