Question

Helium–neon laser light (λ = 632.8 nm) is sent through a 0.350-mm-wide single slit. What is the width of the central maximum on a screen 2.00 m from the slit?

Answer 1

Answer:

The width of the central bright fringe is 7.24 mm.

Explanation:

Given that,

Wavelength = 632.8 nm

Width d= 0.350 mm

Distance between screen and slit D= 2.00 m

We need to calculate the distance

Using formula of distance

$y_{m}=\dfrac{\lambda D}{d}$

Put the value into the formula

$y_{m}=\dfrac{632.8\times10^{-9}\times2.00}{0.350\times10^{-3}}$

$y_{m}=3.62\ mm$

We need to calculate the width of the central bright fringe

Using formula of width

$width = 2\times|y_{m}|$

Put the value into the formula

$width=2\times3.62$

$width = 7.24\ mm$

Hence, The width of the central bright fringe is 7.24 mm.