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Papessa [141]
4 years ago
14

What is the specific heat of a substance that absorbs 228 joules of heat when a sample of 706 g of the substance increases in te

mpature from 26.0 c to 88.8 c
Chemistry
1 answer:
Fudgin [204]4 years ago
6 0

Answer:

c=5.14\ J/kg ^{\circ} C

Explanation:

Given that,

Heat absorbed by a sample, Q = 228 J

Mass of a sample, m = 706 g = 0.706 kg

Initial temperature is 26 °C and final temperature is 88.8°C

We need to find the heat absorbed by the sample. The heat absorbed by an object is given by :

Q=mc\Delta T\\\\\text{Where c is specific heat of sample}\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{228\ J}{0.706\ kg(88.8-26)^{\circ} C}\\\\c=5.14\ J/kg ^{\circ} C

So, the specific heat of the sample is 5.14\ J/kg ^{\circ} C.

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Let's assume that change of pressure of PCl₅ is X

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Initial Pressure       0.123           -             -
Change                   -X               +X          +X
Equilibrium             0.123 - X       X           X

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Read 2 more answers
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